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elena-14-01-66 [18.8K]
4 years ago
7

Richard practice each of three piano solos for 5/12 hour expressed in simplest form how long did he practice in all

Mathematics
1 answer:
kkurt [141]4 years ago
8 0
5/12 hour = 1 piano solo's
15/12 hour = 3 piano solo's

Simplifying 15/12 hours we get:
<u>1.25 hours also known as 1 hour 15 minutes</u>
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Which function has a domain of all real numbers except x=pi/2+-npi?
OLga [1]
It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.
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3 years ago
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40 is the sum of 15 and Craig's savings.<br> Use the variable c to represent Craig's savings.
andrew-mc [135]
40=15+c

Hope it helps
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3 years ago
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mrs. Williams uses the following recipe for crispy rice treats. She decided to make 2/3 of the recipe. 2 cups of melted butter,
Ilya [14]
To find how much she needs of every ingredient, multiply every ingredient by 2/3.

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Ari and Greg share a 12-ounce bucket of clay. By the end of the week, Ari has used 1 6 of the bucket, and Greg has used 2 3 of t
kotegsom [21]

Answer:

2 ounces of clay is left in the bucket

Step-by-step explanation:

Total amount of clay in the bucket = 12 ounce

Ari used 1/6th of the clay in the bucket and Greg used 2/3 of the clay in the bucket

Hence, the remaining clay in the bucket

12 - 1/6 *12 - 2/3 * 12

12 - 2-8

2

3 0
3 years ago
An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
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