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jeka57 [31]
3 years ago
14

2x-y+7whenx= -5andy-2.

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

2x-y+7

Let x = -5 and y = -2

2(-5) -(-2) +7

-10 +2 +7

-10 +9

-1

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Step-by-step explanation:

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Answer:

Option D. 5

Step-by-step explanation:

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frosja888 [35]

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1. \: 3i

2. option D

3. option C

4. option D

5. option C

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Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

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\sqrt{ - 1}  \times  \sqrt{  9}

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<h2>2. \:  \sqrt{ - 8}</h2>

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\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

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<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

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i \times ( {6}^{2}  \times 2)

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<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

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<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

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<h2>8. \:  \sqrt{ - 12}</h2>

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<h2>10. \:  \sqrt{ - 180}</h2>

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i \times  \sqrt{ {6}^{2} \times 5 }

6i \sqrt{5}

<h3>Hope it is helpful...</h3>
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