Step-by-step explanation:
A)
The length of the box is 30 − 2x inches.
The width of the box is 30 − 2x inches.
The height of the box is x inches.
So the volume is:
V = x (30 − 2x)²
B)
V(3) = 3 (30 − 6)² = 1728
V(4) = 4 (30 − 8)² = 1936
V(5) = 5 (30 − 10)² = 2000
V(6) = 6 (30 − 12)² = 1944
V(7) = 7 (30 − 14)² = 1792
As x increases, the volume of the box increases to a maximum and then decreases.
C)
The ends of the domain occur when V = 0.
0 = x (30 − 2x)²
x = 0 or 15
So the domain is (0, 15).
So it’ll be 42 divided by 6 since u want to know how many servings of 6 ounces can be served from a 42 pound bag
So 42/6= 7
Answer
0.22580645161
Step-by-step explanation:
you just have to do 4 3/7 in a calculator
If tangent to the curve y = √x is parallel to the line y = 8x, then this implies that the tangent to y = <span>√x has the same slope as the line y = 8x. In other words, the derivative (slope) function of y = √x is equal to the slope of the line y = 8x, which is m = 8. Hence y' = 8 once we find y'
y = </span><span>√x = x^(1/2)
Applying the power rule and simplifying, we find that the derivative is
y' = 1/(2</span>√x)
Now remember that y' must equal 8
1/(2<span>√x) = 8
Multiplying both sides by 2</span><span>√x, we obtain
1 = 16</span><span>√x
Dividing both sides by 16, yields
</span><span>√x = 1/16
But wait a minute, √x = y. Thus 1/16 must be the y-coordinate of the point at which the tangent to y = √x is drawn.
Squaring both sides, yields
x = 1/256
This is the x-coordinate of the point on the curve where the tangent is drawn.
</span><span>∴ the required point must be (1/256, 1/16)
GOOD LUCK!!!</span>
Pre Image having vertices : △ABC with vertices A(−5, −4), B(−7, 3), C(3, −2)
Image having vertices : △A′B′C′ with vertices A′(−3.75, −3), B′(−5.25, 2.25), C′(2.25, −1.5).
As, Size of Preimage > Size of image
So, 0<Dilation Factor <1
When a triangle is dilated , the preimage and image are similar to each other .
Scale factor can be get through by finding the ratio of any of corresponding sides of triangle.
So, Scale Factor of Dilation = 
