All categories

3 years ago

Write an equation for the direct variation (y varies directly with x) if y=12 when x=4.

Mathematics

1 answer:

Olegator [25]3 years ago

6 0

Hdhssuejzzsxfffdfggfds

You might be interested in

If you found the percent of a number and the product is greater than the number, whatvdo you know about the percent? Explain.

Ganezh [65]

The percent of said number must be over 100% because 100% is the whole value of a number

Ex:
105% of 20 is 21 because, 100% of 20 is 20 and 5% of 20 is 1
150% of 20 is 30 because, 100% of 20 is 20 and 50% of 20 is 10

Hope this helps

5 0

3 years ago

In each box, 15% of the total candies are cherry flavored. In a box of 20 candies, how many are cherry flavored? Enter the missi

Yanka [14]

The answer is 3. I don't know if you want ne to explain or show my work just reply to me.

5 0

3 years ago

Read 2 more answers

Last year the highest temperature in a city was recorded as 23ºC, and the lowest temperature was recorded as -10ºC. How many deg

DerKrebs [107]

33 degrees C

Step-by-step explanation:

On the integer scale, the numeric values can be added thus

23 to -10

23 to 0 and 0 to -10

23-0 = 23

0 -(-10) = 10

23 + 10 = 33

Thus, 33 degree C is the difference between the two temperatures.

5 0

3 years ago

Someone help asap please, thanks!

Sever21 [200]

Graph B is the correct answer

7 0

3 years ago

Show all work and reasoning

Natalija [7]

Split up the interval [2, 5] into $n$ equally spaced subintervals, then consider the value of $f(x)$ at the right endpoint of each subinterval.

The length of the interval is $5-2=3$ , so the length of each subinterval would be $\dfrac3n$ . This means the first rectangle's height would be taken to be $x^2$ when $x=2+\dfrac3n$ , so that the height is $\left(2+\dfrac3n\right)^2$ , and its base would have length $\dfrac{3k}n$ . So the area under $x^2$ over the first subinterval is $\left(2+\dfrac3n\right)^2\dfrac3n$ .

Continuing in this fashion, the area under $x^2$ over the $k$ th subinterval is approximated by $\left(2+\dfrac{3k}n\right)^2\dfrac{3k}n$ , and so the Riemann approximation to the definite integral is

$\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n$

and its value is given exactly by taking $n\to\infty$ . So the answer is D (and the value of the integral is exactly 39).

8 0

3 years ago