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Romashka [77]
3 years ago
6

In each box, 15% of the total candies are cherry flavored. In a box of 20 candies, how many are cherry flavored? Enter the missi

ng value in the box to complete the ratio table.
Mathematics
2 answers:
Yanka [14]3 years ago
5 0
The answer is 3. I don't know if you want ne to explain or show my work just reply to me.
TiliK225 [7]3 years ago
3 0

Answer: There are 3 cherry candies in the box.


Step-by-step explanation:

Given: The total number of candies in a box = 20

Since, 15% of the total candies are cherry flavored.

Then the number of cherry candies = 15% of 20

To convert percent into decimal , divide it by 100 we get

The number of cherry candies =\frac{15}{100}\times20=3

Hence,There are 3 cherry candies in the box.

You might be interested in
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
Show all work to identify the asymptotes and zero of the function f of x equals 5 x over quantity x squared minus 25.
Lorico [155]

Answer:

  • asymptotes: x = -5, x = 5
  • zero: x = 0

Step-by-step explanation:

The function of interest is ...

  f(x)=\dfrac{5x}{x^2-25}=\dfrac{5x}{(x-5)(x+5)}

The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5

__

The zeros are found where the numerator is zero. It will be zero for x = 0.

The asymptotes are x=-5, x=5; the zero is x=0.

4 0
3 years ago
Does anyone get this ???
nikklg [1K]

Answer:

no. sorry. :(

Step-by-step explanation:

8 0
3 years ago
I need help please! The sequence 6,18,54,162, ... shows the number of pushups Kendall did each week, starting with her first wee
Romashka-Z-Leto [24]

Answer:

a: 3

b. 6973568802

Step-by-step explanation:

a₁ = 6 , r = 3 , a₂₀ =?

Result:

a₂₀ = 6973568802

Explanation:

To find a₂₀ we use the formula

aₙ = a₁ · r ^ⁿ⁻¹

In this example we have a₁ = 6 , r = 3 , n = 20. After substituting these values to above

formula, we obtain:

aₙ = a₁ · r ^ⁿ⁻¹

a₂₀ = 6 · 3 ^²⁰⁻¹

a₂₀ = 6 · 1162261467

a₂₀ = 6973568802

3 0
3 years ago
Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options. 6
Murljashka [212]

Answer:

the second one, ((6 x 5) x 4) +((5 x 4) x 2) = 160

the third one, ((7 x 6) x 4) + (6 x 4) x 2) = 216

the fourth one, ((8 x 4) x 4) + ((4 x 3) x 2) = 152

Step-by-step explanation:

7 0
3 years ago
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