Ask question

Ask question

All categories

wolverine [178]

3 years ago

9

In Whitehorse, the high temperature for the day was 7°C, and in Yellowknife the high for the same day was -8°C. What was the dif

ference in high temperature between the two cities?

1 answer:

Lesechka [4]3 years ago

6 0

The difference between the two cities are that each temp is different their 14c away because their is a minus on the eight

You might be interested in

Graph y = | x | + 5

Elanso [62]

Answer:

(0,5) (0,-5)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The Enterprise High School girl's soccer team won 80% of their games last year if the team won 12 games how many did they play?

jasenka [17]

I gizg A Tduuiy gf dryfchv u

3 0

3 years ago

FIND THE AREA...!!!!!

k0ka [10]

I think C I’m not sure but if you want me to explain I multiplied 12 x 10 and 20 x 6 and they both equal 120. So then I added 120 + 120 and got 240. Then u just added 8 because 8 was never use. Which will now look like 240 + 8 and that equal 248. :)

3 0

3 years ago

Which statement is not always true?

Fed [463]

Statement #3: The product of two irrational numbers is not always irrational.

If you multiply √3 and 1/√3, both irrational numbers that are inverses of each other, you end up getting 1, which is rational.

4 0

3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago