Solve pls brainliest
1 answer:
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Answer:
A. dilation by a scale factor of 1/3
B. translation to the left 4 units
C. translation down 3 units
Step-by-step explanation:
On a coordinate plane,
triangle A has points (3, 3), (6, 3), (6, 9).
Triangle A prime has points (negative 2, negative 1), (negative 2, negative 2), (negative 3, negative 2).
Determine all the transformations needed to transform the pre-image, A, to the image, A'.
Select all that apply, given
A=(3,3),(6,3),(6,9)
A'=(-2,-1),(-2,-2),(-3,-2) possible typo, should read
A'=(-2,0),(-2,-2),(-3,-2)
dilation by a scale factor of 1/2
dilation by a scale factor of 1/3
reflection over the x-axis
translation to the left 4 units
translation down 3 units
If the typo correction is valid, then the transformatitons are:
A. dilation by a scale factor of 1/3
B. translation to the left 4 units
C. translation down 3 units
A polynomial of degree 3 has exactly 3 solutions if we use complex numbers. If the polynomial has real coefficients and z is a complex solution, i.e., , the conjugate is also a solution:
So, in the first case, if we know that 1-i is a solution, the conjugate 1+i must be a solution as well.
So, we know all the roots: -5, 1+i, 1-i.
When you know the solutions of a polynomial, you can write the polynomial (up to multiples) as
So, in your case, we have
You can check that indeed , because the constant term is 10, so, we're ok with this
The second exercise is exactly the same: the solutions -6, i, -i identify the polynomial
In this case, P(-3)=30, so if we want P(-3)=60 we have to multiply everything by 2: