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taurus [48]
2 years ago
7

(brainliest) please help! :D

Mathematics
1 answer:
tekilochka [14]2 years ago
3 0

Answer:

Answer is Number 2

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A bag of marbles contains 16 blue, 8 green, 9 red, 12 yellow and 5 black marbles. What is the probability of drawing a green mar
alexgriva [62]

Answer:

8/50

Step-by-step explanation:

you would take the number of that colored marble which in this case is green so now we have our numerator which is 8 next we are going to add all of the amount of numbers including the green and we get 50 and 50 is our denominator.

8 0
3 years ago
Tara earns $9 for each dog she walks. She walks 10 dogs an hour. After walking dogs for 4 hours, how much money will Tara have e
solong [7]

Answer: $360

Step-by-step explanation:

In one hour, she makes $9 * 10 dogs = $90.

In 4 hours, we simply multiply that by 4 to get $90 * 4 = $360 total

4 0
3 years ago
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The difference of sample means of two populations is 55.4, and the standard deviation of the difference of sample means is 28.1.
Anna [14]

Answer:

The difference of the two means is not significant, so the null hypothesis must be rejected.


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3 years ago
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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
What is equivalent to <img src="https://tex.z-dn.net/?f=%283%5E6%293" id="TexFormula1" title="(3^6)3" alt="(3^6)3" align="absmid
kherson [118]

For this case we must indicate an expression equivalent to:

(3 ^ 6) ^ 3

For properties of powers we have to:

(a ^ n) ^ m = a ^ {n * m}

So, the above expression can be rewritten as:

(3 ^ 6) ^ 3 = 3^{6*3} = 3^{18}

Thus, the resulting expression is: 3^{ 18}

Answer:

3^{ 18}

Option D

8 0
3 years ago
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