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klemol [59]
3 years ago
14

Find the sum or difference (5b-9)-3(8-2b)

Mathematics
2 answers:
vekshin13 years ago
8 0
-3(8-2b)

-24 + 6b + 5b - 9

-15b + 11b.

Can also be expressed as 11(b - 3)
True [87]3 years ago
5 0
<span>Simplifying (5b + -9) + -3(8 + -2b) = 0 Reorder the terms: (-9 + 5b) + -3(8 + -2b) = 0 Remove parenthesis around (-9 + 5b) -9 + 5b + -3(8 + -2b) = 0 -9 + 5b + (8 * -3 + -2b * -3) = 0 -9 + 5b + (-24 + 6b) = 0 Reorder the terms: -9 + -24 + 5b + 6b = 0 Combine like terms: -9 + -24 = -33 -33 + 5b + 6b = 0 Combine like terms: 5b + 6b = 11b -33 + 11b = 0 Solving -33 + 11b = 0 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '33' to each side of the equation. -33 + 33 + 11b = 0 + 33 Combine like terms: -33 + 33 = 0 0 + 11b = 0 + 33 11b = 0 + 33 Combine like terms: 0 + 33 = 33 11b = 33</span>
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For the given expressions we will have:

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y = exp(x) + 7 → we have a shift of 7 units up.

y = exp(x) - 6  → we have a shift of 6 units down.

<h3>How to work with vertical and horizontal shifts?</h3>

Remember that the shifts work as follows.

For a function f(x), we define a vertical shift of N units as:

g(x) = f(x) + N

  • If N > 0, the shift is upwards.
  • If N < 0, the shift is downwards.

For a function f(x), we define a horizontal shift of N units as:

g(x) = f(x + N)

  • If N > 0, the shift is to the left.
  • If N < 0, the shift is to the right.

Then, if we have:

exp(x - 4) we have a shift of 4 units to the right.

exp (x +9) we have a shift of 9 units to the left.

exp(x) + 7 we have a shift of 7 units up.

exp(x) - 6  we have a shift of 6 units down.

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1 year ago
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S_A_V [24]

Answer:

Step-by-step explanation:

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If Ann travels 50 meters North, 200 meters East and 150 meters South, what is her total distance travelled ? A. 150 meters B.400
olga2289 [7]

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400 meters

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3 years ago
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Answer:

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Step-by-step explanation:

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Find the second derivative of 2x^3-3y^2=8​
Umnica [9.8K]

Answer:

\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}

Step-by-step explanation:

<u>Find the first implicit derivative using implicit differentiation</u>

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2 years ago
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