Question

The square root of t is greater than 2 and less than 3.5. How many integer values of t satisfy this condition?

Answer 1

We are given that: $2 < \sqrt{t} < 3.5$, so if we want to find out what t satisfies this, we have to square all of the compound inequality, giving us:

$4$

So, the integers on this interval are clearly just 5,6,7,8,9,10,11 and 12. That means there are 8 integer values of t that fits the new inequality, so there are 8 roots of t that give us a value between 2 and 3.5

Answer 2

$2$

8 integers