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mojhsa [17]
3 years ago
11

Geometry proofs Need help!!

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

Angles ∠MOK and ∠NOL are identical by opposite angle theorem.

∠M = ∠N through given information

∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO  = ∠NLO by stating that the opposite sides of the two angles are congruent.

ΔMKO and ΔNLO by Angle-Angle-Side theorem

since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO

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Compare and contrast the solution of |2x + 8| > 6 and the solution of |2x + 8| < 6.
svet-max [94.6K]

Answer:

B.

The solution of |2x + 8| > 6 includes all values that are less than –7 or greater than –1.

The solution of |2x + 8| < 6 includes all values that are greater than –7 and less than –1.

__

Step-by-step explanation:

You can find the solution by "unfolding" the absolute value, then dividing by 2 and subtracting 4:

-6 > 2x +8 > 6 . . . . . read this as -6 is less than 2x+8 or 2x+8 is greater than 6

-3 > x +4 > 3 . . . . . . .divide by 2

-7 > x > -1 . . . . . . . . . solution to the first inequality: x is less than -7 or greater than -1.

___

The solution to the other inequality is identical, except the direction of the comparison is reversed. It is read differently, because the segments overlap, rather than being disjoint.

-7 < x < -1 . . . . . . . . solution to the second inequality: x is greater than -7 and less than -1.

__

These descriptions match choice B.

3 0
3 years ago
A group of friends wants to go to the amusement park. They have no more than $155
seraphim [82]

Answer:

9 people can go

Step-by-step explanation:

6.50 is a one-time deal. we take that away once and we're done with it.

155 - 6.50 = 148.5

148.5 / 16.50 = 9

4 0
2 years ago
(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
3 years ago
You collect a total of $75 in donations from three people. The three donations are in the ratio 4 : 4 : 7. (hint: set up an equa
Amanda [17]

Answer:

Step-by-step explanation:

Since the ratio is 4x:4x:7x, if we add all those numbers up we get 15. Then we do 75/15 to get what x equals. So we get 5. So x equals 5. Following the rules of multiplication, you do 4(5):4(5):7(5), and simplifying that further, you get 20:20:35. If we add all those values up, we should get 75, and we do!

If you're wondering why I did 4x:4x:7x instead of 4:4:7, it's because a ratio is just a...well ratio? It's easier to visualize if you put a variable because the variable could be anything, and you would have to multiply all the given values to get the same proportions. In summery, I did it so it was easier to visualize

3 0
3 years ago
X^2 - 36 = 0.
strojnjashka [21]

Answer:

(x+6)(x−6)=0

x=-6 or x=6

Step-by-step explanation:

X^2 - 36 = 0

Solve by Square Root

add 36 both sides

x^2−36+36=0+36

x^2=36

square root

x=±√36

x=6 or x=−6

You can do that or for 2nd option

Solve by factoring

x^2-36=0

(x+6)(x−6)=0

Set factors equal to 0

x+6=0 or x−6=0

x=-6 or x=6

PLEASE NOTE: 36 is the square of 6

and

x2  is the square of  x1

8 0
3 years ago
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