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3 years ago

I need help on this!!!

Mathematics

2 answers:

MrRa [10]3 years ago

8 0

Step-by-step explanation:

3 tickets = $16.50

1 tickets = $16.50/3

= $5.5

2 tickets = $2×5.5

= $11.00

Anuta_ua [19.1K]3 years ago

4 0

You would do 16.50 divided by 3 to get the cost of one of the tickets so that would be 5.5 and then multiply by 2 to get 11! So your answer is 11

I hope this helped :))

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A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98%

Luden [163]

Answer:

a) z = 2.327

b) The margin of error is of 0.065.

c) The 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate is (0.3083, 0.4383).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 300, \pi = \frac{112}{300} = 0.3733$

a) 98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $z = 2.327$ is the critical value.

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

So, applying to this question:

$M = 2.327\sqrt{\frac{0.3733(1-0.3733)}{300}} = 0.065$

The margin of error is of 0.065.

c) Find confidence interval for the problem.

$\pi - M = 0.3733 - 0.065 = 0.3083$

$\pi + M = 0.3733 + 0.065 = 0.4383$

The 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate is (0.3083, 0.4383).

3 0

3 years ago

In how many year the interest will became equal to the principal is rs.1200 is deposited at the rate of 25% in a bank

mrs_skeptik [129]

Given:

Principal = Rs. 1200

Rate of interest = 25%

To find:

The time in which the interest will became equal to the principal.

Solution:

We have,

$P=1200$