The mean of a normally distributed dataset is 12, and the standard deviation is 2.

2 answers:

7 0

In the Normal distribution: if the mean (M) is 12 and the standard deviation (s)is 2, then between 8 (12- 2*2, or M - 2 s) and 16 (12 + 2*2, or M+2 s ),or between M - 2 s and M + 2 s lies 13.6 %+ 34.1% + 34.1 % + 13.6% = 95.4% data points. Graph is in the attachment.

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ANEK [815]3 years ago

4 0

The correct answer is:

95%

Explanation:

The empirical rule states that 68% of normally distributed data lie within 1 standard deviation of the mean; 95% lie within 2 standard deviations of the mean; and 99.7% lie within 3 standard deviations of the mean.

The mean is 12 and the standard deviation is 2. This means that values from 10 to 14 (12-2, 12+2) are within 1 standard deviation of the mean.

Values from 8 to 16 (12-2-2, 12+2+2) are within 2 standard deviations of the mean. These are the values in question; this means that 95% of the data lie within this range.

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A newsgroup is interested in constructing a 90% confidence interval for the proportion of all Americans who are in favor of a ne

Evgen [1.6K]

Answer:

a. With 90% confidence the proportion of all Americans who favor the new Green initiative is between 0.6290 and 0.6948.

b. If the sample size is changed, the confidence interval changes as the standard error depends on sample size.

About 90% percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about 10% percent will not contain the true population proportion.

Step-by-step explanation:

We have to calculate a 90% confidence interval for the proportion.

The sample proportion is p=0.6619.

$p=X/n=370/559=0.6619$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.6619*0.3381}{559}}\\\\\\ \sigma_p=\sqrt{0.0004}=0.02$

The critical z-value for a 90% confidence interval is z=1.6449.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=1.6449 \cdot 0.02=0.0329$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.6619-0.0329=0.6290\\\\UL=p+z \cdot \sigma_p = 0.6619+0.0329=0.6948$

The 90% confidence interval for the population proportion is (0.6290, 0.6948).

3 0

2 years ago

Convert 27/20 to a decimal

Tatiana [17]

27/20

= 20/20 + 7/20

= 1 + 7/20

= 1.00 + 0.35

= 1.35

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List of values to remember (extras):

0.05 = 1/20 = 5%
0.10 = 1/10 = 10%
0.15 = 3/20 = 15%
0.20 = 1/5 = 20%
0.25 = 1/4 = 25%
0.30 = 3/10 = 30%
0.35 = 7/20 = 35%
0.40 = 2/5 = 40%
0.45 = 9/20 = 45%
0.50 = 1/2 = 50%
0.55 = 11/20 = 55%
0.60 = 3/5 = 60%
0.65 = 13/20 = 65%
0.70 = 7/10 = 70%
0.75 = 3/4 = 75%
0.80 = 4/5 = 80%
0.85 = 17/20 = 85%
0.90 = 9/10 = 90%
0.95 = 19/20 = 95%
1.00 = 1 = 100%

8 0

3 years ago

Read 2 more answers

Anybody? need help asap

VladimirAG [237]

Answer:

K=2h

k=0.5h

k=h + 1

k= 0.5h + 10

7 0

2 years ago