Question

The length of a rectangle is 4 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 72 cm.
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Answer 1

Let, the width = x
length = 2x - 4

Perimeter = 2(l+w)
Substitute their values, 
72 = 2(x+2x-4)
72 = 2(3x-4)
6x - 8 = 72
6x = 80
x = 80/6
x = 13.3

In short, Your Answer would be 13.33 cm

Hope this helps!