3 years ago

Find dy/dx (derivative) using Implicit Differentiation: xe^y=x-y

1 answer:

6 0

D (xe^y)/dx = d(x - y)dx
(e^y)dx/dx + xd(e^y)/dx = 1 - y'
e^y + xy'e^y = 1 - y'
(1 + xe^y)y' = 1 - e^y
y' = (1 - e^y)/(1 + xe^y)

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kozerog [31]

Answer:

B= $\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]$

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Let's do the multiplication AB.

If A= $\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]$

then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.

the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.

the second row of A is= (0 0) by any colum of B is equal to zero too.

So we have found an example that works!

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C 495 i know its right.

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