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Dimas [21]
3 years ago
10

38.7÷4.5 and plz show your work of you can thank you

Mathematics
2 answers:
serg [7]3 years ago
4 0
I hope this helps you

forsale [732]3 years ago
4 0
Here is the answer and work

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Solve.
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Step-by-step explanation:

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Which line represents a horizontal asymptote of f (x) = StartFraction 5 x squared minus 3 x + 2 Over 10 x squared minus 1 EndFra
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3 years ago
Read 2 more answers
Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I
fredd [130]

Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

<em>x =4</em>

Step-by-step explanation:

<u>First factorize the function</u>

f (x) = -2x ^ 2 + 16x-30

<em>Take -2 as a common factor.</em>

-2(x ^ 2 -8x +15)

<em>Now factor the expression x ^ 2 -8x +15</em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

f (x) = -2(x-5)(x-3)

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form ax ^ 2 + bx + c the x coordinate of its vertex is:

x = \frac{-b}{2a}

In the function f (x) = -2x ^ 2 + 16x-30

a = -2\\b = 16\\c = 30

<u>Then the vertice is:</u>

x = \frac{-16}{2(-2)}\\\\x = 4

The y coordinate of the symmetry axis is

y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

x = 4

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

6 0
3 years ago
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