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Harlamova29_29 [7]
2 years ago
8

Evaluate 6 64 × 8 15 Give your answer as a fraction in its simplest form.?

Mathematics
1 answer:
Mumz [18]2 years ago
7 0

Answer:

The simplest form is 1/20

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Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]​
telo118 [61]

Answer:

5 × [5(-7)]

= 5 × (-35)   ---- 5 × (-7) = -35

= -175

4 0
3 years ago
Help it’s homework!!!!
Airida [17]

Answer:

(3x - 3)(x + 2)

Step-by-step explanation:

3x^2 + 3x - 6

(3x^2 + 6x)(-3x - 6)

3x(x + 2) -3(x + 2)

(3x - 3)(x + 2)

3 0
3 years ago
Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).
Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

m_1=\frac{7-0}{3-0}=\frac{7}{3}

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)

The slope of the line joining E(7,0), and F(3,7). is:

m_1=\frac{7-0}{3-7}=-\frac{7}{4}

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

4 0
3 years ago
Evaluate 3^2 + (6-2) × 4 - 6/3​
IrinaVladis [17]
Answer: 23
Explanation: simplify using PEMDAS so solve parentheses, then solve the exponent, multiply the second number by 4, and then add, then subtract.

Hope this helps!
4 0
2 years ago
The perimeter of the square can be represented by the expression 36x+44 robin wants to write an equivalent expression for the pe
sukhopar [10]

Answer:

4  (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

Step-by-step explanation:

Here, given The perimeter of the square  = (36 x+44)

Now,as we know :

PERIMETER OF SQUARE = 4 x ( SIDES)

Simplifying the perimeter expression.

Take 4 common out of the expression (36 x+44), we get:

(36 x+44) =  4 (9 x + 11)

⇒ Perimeter of the square  =  4 x  (9 x + 11)

⇒4 x ( SIDES) = 4 x (9 x + 11)

⇒ Each Side = (9 x + 11)

Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

5 0
3 years ago
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