Evaluate 6 64 × 8 15 Give your answer as a fraction in its simplest form.?

Help me out pleaseee

spayn [35]

Answer:

Option B is the correct choice.

Step-by-step explanation:

The graph is attached below.

We have to find the $x$ intercept meaning the value of the point on $x-axis$ when $y=0$

So we will put the value of zero $(0)$ instead of $y$ in our given equation.

So here we have solved it algebraically.

$y=\frac{3}{4}x-3$

Putting $y=0$

$0=\frac{3}{4}x-3$

$0=\frac{3x-12}{4}$

Multiplying $4$ both sides.

$0=3x-12$

Adding $12$ both sides.

$12=3x$

Dividing with $3$ both sides.

$x=\frac{12}{3}=4$

So the x-intercept of the given equation is $4$ which can be written as $(4,0)$ in terms of coordinates.

Option B $(4,0)$ is the correct choice.

8 0

3 years ago

Please help very urgent on test...

stepladder [879]

Answer:

Equation: (2x+5)4=(2x+8)3

X: 2

Perimeter: 36

Step-by-step explanation:

You would multiply 2x+5 and 4 because there are four sides to a square, so the perimeter of the square would be 8x+20. This would go same for the triangle, making the perimeter 6x+24.

So 8x+20=6x+24 is your new equation. Then, you do the opposite of the order of operations, and add or subtract first. It would be easiest to subtract 20 and 6x from both sides.

That leaves you with 2x=4. Dividing 2 by both sides means x=2

You can plug this in to prove if it is correct.

16+20=36

12+24=36

Lmk if you get it!

8 0

3 years ago

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9

Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that $\mu = 8.9, \sigma = 2.9$

Sample of 37:

This means that $n = 37, s = \frac{2.9}{\sqrt{37}}$

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -0.53$

$Z = -0.53$ has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -3.08$

$Z = -3.08$ has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0

2 years ago

Write an equation for the graph, where y depends on x.

Over [174]

Answer:

y = -3x + 6

Step-by-step explanation:

Equation of straight line is given by,

y = mx + b

m = slope of the line

b = y-intercept

From the graph attached,

m = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{-6}{2}$

= -3

y intercept 'b' = 6

Therefore, equation of the line will be,

y = -3x + 6

5 0

3 years ago

How can you use an equation to make a prediction from a pattern?

Vanyuwa [196]

Upon formation of an equation from a given pattern, we know how the variables in the patter are related. Using the equation, we can find the value of one of the missing variables if the rest are known and also predict the values of the pattern at given conditions.
An example:
y = 2x + 5
if we are to predict the value of y at x = 3, we simply substitute 3 into x
y = 2(3) + 5
= 11

8 0

2 years ago

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