The answer is: 54 inches would be too long for a shoelace
If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)
<span>Answer:
K = (1/2) mv² + (1/2) Iω², where m is the ball mass, I is the ball's moment of inertia (2/5)mr², and ω is the angular velocity of the ball. Because the ball rolls without slipping, it is easy to see that v=ωr, or r=v/ω. Then,
K = (1/2)mv² + (1/2)(2/5)mr²ω²
= (1/2)mv² + (1/5)mv²
= (7/10)mv²
Setting potential at the top equal to kinetic at the bottom,
mgh=(7/10)mv²
v=âš{(10/7)(gh)}
= [(10/7)(9.8)(0.51)]^(1/2) = 2.672m/s</span>
Answer: The area of the enclosure is 1,029 square meters
Step-by-step explanation: The first thing is to use the unit of measurement required by the question, and to do this we need to convert what we have to what is required.
If the scale of the diagram is given as every 4cm represents 7m, that means, every unit of the actual measurement would be given as
(X/4) x 7
For the length of the enclosure, we can determine that as follows;
Length = (28/4) x 7
Length = 7 x 7
Length = 49m
And for the width,
Width = (12/4) x 7
Width = 3 x 7
Width = 21m
Therefore, the area is calculated as,
Area = L x W
Area = 49 x 21
Area = 1029 m²
The answer would be 10 to the third because if you divide that it would equal 1,000