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Mazyrski [523]
3 years ago
13

The square root of 61 is in between 2 integers what are they

Mathematics
1 answer:
swat323 years ago
8 0
One way is to estimate
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
6^2=36
7^2=49
8^2=64
the number 61 is between 49 and 64 therefor the square root of 61is between the intigers 7 and 8 or -7 and -8
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<u>Answer:</u>

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<u>Explanation</u>:

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Step-by-step explanation:

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[ Let f ( x ) ] = [ 3 x 2 + 2 x ] , [ g ( x ) ] = [ 3 x + 9 ] , [ h ( x ) ] = [ 12 + x ] , [ What is f ( g ( 3 ) ) ? ] [ Let f (
Pachacha [2.7K]

Answer:

The value of f(g(3) =  1,008

Step-by-step explanation:

<u>Step:-1</u>

Given f(x) =3 x ^ 2 + 2 x

and g(x) = 3x+9

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Given g(x) = 3x+9

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<u>Step :-(2)</u>

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<u>Final answer</u>:-

The value of f(g(3) =  1,008

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