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zloy xaker [14]
3 years ago
7

1.9.PS-16

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Answer:

0.06245

Step-by-step explanation:

Decrease 7/12=0.583

from 9 p.m to 6:20 am is 9:20= (9+20/60) = 9.33 hours

0.583/9.33 = 0.06248

round the 0.06248 to 0.06245

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Solve the problem. Find the surface area of a right regular hexagonal pyramid with sides 2 cm and slant height 5 cm. Round youra
BabaBlast [244]

Answer:

The surface area of the right regular hexagonal pyramid is 50.78 cm².

Step-by-step explanation:

Given:

A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.

Now, to find the surface area(SA) of the right regular hexagonal pyramid.

So, we find the area of the base(b) first:

Area of the base = \sqrt[3]{3}\times s^{2}

                            = \sqrt[3]{3}\times 2^{2}

On solving we get:

Area of the base(b) = 20.784

Then, we find the perimeter(p) :

Perimeter = s × 6

p=2\times 6=12

Now, putting the formula for getting the surface area:

Surface area = perimeter × height/2 + Area of the base.

SA=\frac{p\times h}{2}+b

SA=\frac{12\times 5}{2}+20.784

SA=30+20.784

SA=50.784

As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>

Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².

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The height of a doorway is 7 yards. What is the height of the doorway in inches?
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Answer:

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Step-by-step explanation:

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