8x^5 +4x^2 - 12
= 4(2x^5 + x^2 -3)
answer is A
Answer:
Step-by-step explanation:
Oops I meant "there are 3! = 6 ways to permute ABTS that have TS."
Answer:
3(2x+11)= 6x+33 and (3x+15)(2) = 6x+30
Step-by-step explanation:
Use distributive property to multiply the outside factor to each factor inside the parenthesis.
3(2x+11)
(3*2x)+(3*11)
6x+33
Answer:
35 glasses of classic milk tea
15 glasses of flavored milk tea
Step-by-step explanation:
You sold 50 glasses of classic and flavored milk tea.
c + f = 50
You made 4700 when classic tea costs 100 and flavored tea costs 80.
100c + 80f = 4700
Use this system of equation to solve. Use substitution. Rearrange the first equation so that it is equal to c. Then, plug the c-value into the second equation.
c + f = 50
c = 50 - f
100c + 80f = 4700
100(50 - f) + 80f = 4700
5000 - 100f + 80f = 4700
5000 - 20f = 4700
-20f = -300
f = 15
Plug the f-value into one of the equations and solve for c.
c + f = 50
c + 15 = 50
c = 35
35 glasses of classic milk tea and 15 glasses of flavored milk tea were sold.
Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ±
]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.

So






n= 147.28 ≅ 148 boxes.
I hope it helps!