What is the area of the figure?
1 answer:
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Answer:
Option b.
Step-by-step explanation:
Given : is right angled triangle . An altitude is drawn from point R to point T on side S Q to form a right angle. The length of S T is 9 and the length of T Q is 16. The length of S R is x.
In the figure, and RT is perpendicular to SQ.
We know that in a right angled triangle if a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the perpendicular are similar to each other and to the whole triangle .
Therefore ,
Also, we know that if two triangles are similar then their sides are proportional .
So, option b. is correct
A. The perimeter of quadrilaterals are same when x=2.
B. The area of quadrilaterals are same when x=4.6
<u>Step-by-step explanation</u>:
A. <u>Perimeter of the quadrilaterals must be equal.</u>
- Perimeter of square is 4a.
- where, a = 6
- Perimeter of rectangle is 2(l+b).
- where, l = 2 and b = (3x+4)
Perimeter of square = Perimeter of rectangle
4(6) = 2(2+3x+4)
⇒ 24 = 2(3x+6)
⇒ 24 = 6x + 12
⇒ 6x = 12
⇒ x = 12/6
x = 2
For x=2, the perimeters of both the quadrilaterals are same.
B. <u>Area of the quadrilaterals must be equal.</u>
- Area of square is a².
- where, a = 6.
- Area of rectangle is l
b.
- where, l = 2 and b = (3x+4)
Area of square = Area of rectangle
(6)² = 2(3x+4)
36 = 6x+8
6x = 28
x = 28/6
x = 4.6
For x=4.6, the area of both the quadrilaterals are same.