Answer:
It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.
Step-by-step explanation:
![\huge\fbox\green{ANSWER}](https://tex.z-dn.net/?f=%20%5Chuge%5Cfbox%5Cgreen%7BANSWER%7D%20)
Surface Area = 2×(8.25×1.5 + 8.25×3 + 1.5×3) = 83.25 centimeters^2
![\mathsf \blue{83.25 {cm}^{2} }](https://tex.z-dn.net/?f=%20%5Cmathsf%20%5Cblue%7B83.25%20%7Bcm%7D%5E%7B2%7D%20%7D)
Answer:
Step-by-step explanation:
i ASSUME THE QUESTION IS TO DETERMINE Y?
Rearrange the equation to y = 2x - 1 and solve for each value of x
<u>X</u> <u>Y</u>
-4 -9
-3 -7
-2 -5
1 1
0 -1
Answer:
$105.25
Step-by-step explanation:
First we need to know to price of the blender after the sale, so we are going to pay the 88% of the blender's price so the final price without the sale tax is going to be
(1)
Knowing this price we need to calculate the 8% of the total price
(2)
We substract the result (2) from (1)
![\$ 114.4 - \$ 9.152 = 105.248](https://tex.z-dn.net/?f=%5C%24%20114.4%20-%20%5C%24%209.152%20%3D%20105.248)
Rounding this number to nearest cent the final result is:
$105.25
Let
![k](https://tex.z-dn.net/?f=k)
be an integer. Suppose there is a triangle with legs of length 16 and
![2k+1](https://tex.z-dn.net/?f=2k%2B1)
. Then by the Pythagorean theorem, the length of the hypotenuse should be
![\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}](https://tex.z-dn.net/?f=%5Csqrt%7B16%5E2%2B%282k%2B1%29%5E2%7D%3D%5Csqrt%7B4k%5E2%2B4k%2B257%7D)
The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if
![x=16](https://tex.z-dn.net/?f=x%3D16)
and
![y=2k+1](https://tex.z-dn.net/?f=y%3D2k%2B1)
are integers, then so are
![x^2-y^2](https://tex.z-dn.net/?f=x%5E2-y%5E2)
,
![2xy](https://tex.z-dn.net/?f=2xy)
, and
![x^2+y^2](https://tex.z-dn.net/?f=x%5E2%2By%5E2)
.
However,
![4k^2+4k+257](https://tex.z-dn.net/?f=4k%5E2%2B4k%2B257)
is not a perfect square trinomial, which means for any integer
![k](https://tex.z-dn.net/?f=k)
, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.