Answer:
f(1) = 16
Domain: 0 ≤ t ≤ 2
Step-by-step explanation:
Given
f(t) = -16t²+ 32t
Solving (a): f(1)
Substitute 1 for t in f(t)
f(t) =− 16t²+ 32t .
f(1) =− 16 * (1)²+ 32 * 1
f(1) = -16 * 1 + 32
f(1) = -16 + 32
f(1) = 16
Solving (b): The domain
The implication of the given parameter in (b) is that t ≤ 2.
Since t represents time, t can't be negative.
Hence, a reasonable domain is
0 ≤ t ≤ 2
-0.8 = -0.8/10
-0.8 x 10 = -8
<span>1 × 10 = 10</span>
<span>-8/10
Simplified = -4/5
</span>
Answer:
1) Solutions are x = 3 and x = 5/3
2) Solution are x ≤ 13/2 and x ≤ -3/2
Step-by-step explanation:
1) Given absolute inequality,
|3x-7| = 2
⇒ 3x - 7 = ± 2
⇒ 3x = 7 ± 2
2) l 2x-5 l ≤ 8
⇒ 2x-5 ≤ ±8
⇒ 2x ≤ 5 ± 8
Answer:
all work is shown and pictured
i think it would take about three minutes
