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dedylja [7]
2 years ago
9

Plz Help I will give Brainliest

Mathematics
1 answer:
Mandarinka [93]2 years ago
7 0

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 8.6 Ft^2

Explanation:

First find the area of the WHOLE square in FEET

2.5 x 4.5 = 11.25 ft

Then we need to find the area of the circle

r = radius

The formula is A = 3.14r^2

The radius is .9166, we can tell because the total distance from top to bottom is 22in meaning 1.83333 ft, meaning the diameter is 1.8333, then to get the radius we cut that in half.

A = 3.14(.9166^2

A = 2.64 Ft

Now we need to find the new total area

11.25 - 2.64 = 8.61 in ^2

Now we need to convert it to the nearest tenth of a square foot

8.6 Ft^2

I hope this helped  !

<!>   Brainliest is appreciated! <!>

-  Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

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Which of the following sets are subspaces of R3 ?
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The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

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for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

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for point C: \to C={(x,y,z)|x

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The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

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