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Oksi-84 [34.3K]

3 years ago

15

45% of 60 Whats the answer? Please add a model. If you can.

2 answers:

n200080 [17]3 years ago

3 0

I dont have a model, sorry. The answer to your Q is: 27. 45% of 60,00, equals to 27,00.

Vlad [161]3 years ago

3 0

<span>45% of 60 = (45/100)·(60/1) = 2700/100 = 27

$\it p \% \ of \ x = \dfrac{p}{100} \cdot x
\\\;\\ \\\;\\
20\%\ of\ 80 = \dfrac{20}{100}\cdot 80 = \dfrac{1600}{100} = 16$

</span>

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Answer:

subtract the number you have from the number you're going to. For example, if you were trying to figure out the distance between 6 and 18, you would subtract 6 from 18 which is 12. I hope this answers your question!

Step-by-step explanation:

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3 years ago

Considering the middle 95% of the data, determine the margin of error, to the nearest hundredth, for the simulated results. In t

nikdorinn [45]

The 95% margin of error simony states that there is a 95% probability that the confidence interval contains the true population mean.

<h3>What is a margin of error?</h3>

It should be noted that the margin of error simply means a measurement that accounts for the difference between the actual result and the projected result in a survey sample.

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2 years ago

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3 years ago

A 90% confidence interval for the mean height of students

Westkost [7]

Answer:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean $\mu$ is given by this formula:

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

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The confidence interval calculated on this case is $60.128 \leq \mu \leq 69.397$

The margin of error for this confidence interval is given by:

$ME =t_{\alpha/2} \frac{s}{\sqrt{n}}$

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

$ME = \frac{Upper -Lower}{2}$

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

$ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635$

And the best answer on this case would be:

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4 0

3 years ago

Suppose you invest 1600 at annual interest rate of 7.9% compounded cont how much will u have after 10yrs

frez [133]

Answer:

B. $3525.43

Step-by-step explanation:

We will use continuously compound interest formula to solve our problem.

$A=P*e^{rT}$

A= Amount after T years.

P= Principal amount.

r= Interest rate (in decimal form).

e= The mathematical constant e.

T= Time in years.

First of all we will convert our interest rate in decimal form.

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Now let us substitute our given values in above formula.

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Therefore, we will get an amount of $3525.43 after 10 years and option B is the correct choice.

8 0

3 years ago