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4 years ago

10

As the owner of a small restaurant, you purchase 5 boxes of napkins for $75.00 every 3 months. Each box contains 525

1 answer:

Alika [10]4 years ago

6 0

Answer:

875

Step-by-step explanation:

Total number of napkins: 5 x 525 = 2,625

2625

3

= 875

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What is the sale price for your purchase if you have a 20% off coupon and you buy a shirt for $19.99 and pants for $10.

Andrew [12]

Answer: I believe it is $23.99

Explanation:
19.99+10= 29.99
29.99x0.2= 5.992
29.99-5.99= $23.99

I hope this helped!

4 0

3 years ago

At what point does a line with a slope of 34 and a y-intercept of -5 intersect a line with a slope of −14 and a y-intercept of 3

maw [93]

Set them into slope-intercept forms of equations then set those equations equal to each other and solve for x and y. y = 34x - 5 and y = -14x+3. Set those equal to each other, solve for x to get x = 1/6. Sub in that x value to get y = 2/3. The point where they intersect is the solution of the system; in other words, where on both lines we have the exact same (x, y) value.

4 0

3 years ago

HELP ASAP PLEASE I HAVE TO TURN THIS IN SOON

Rom4ik [11]

Answer:

B

Step-by-step explanation:

It has a slope of -1/4

and it's y intercept is 2

y = -1/4x + 2

7 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

<u>case b)</u> $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

<u>case c)</u> $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

<u>case d)</u> $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

$x^{2}-2x-4=0$

5 0

3 years ago

Read 2 more answers

Which of the following shows the correct order of the numbers below? (1/2) 2 , , 0.45

Elodia [21]

The correct order would be 0.45, (1/2), 2
Hope I helped :)

8 0

3 years ago