Answer:
8000•1.05 8000(1.05)¹
(8000•1.05)•1.05 8000(1.05)²
((8000•1.05)•1.05)•1.05 8000(1.05)³
(((8000•1.05)•1.05)•1.05)•1.05 8000(1.05)⁴
8000(1.05)^t
Answer:
5.264 * 10^4
Step-by-step explanation:
We put a decimal point to the right of the number, so
52640.
Then we move it to the left until we get a number that is between 1 and 10.
5.2640
This was four hops to the left.
We can remove the trailing 0, and write
5.264 * 10^4
10^4 because of the four hops
1.)
Old Number:35
New Number:45
Now, subract the new number(45) from the old number. (35)
45-35 is 10. Now divide the old number (35) by 10.
You'll get 3.5. 3.5%, increase is the answer for #1.
2.) Old: s (students)
New: 36,750
Do 100+5 (Addition because we do not know what the old number is.) 100+5 is 105. Move decimal over twice and you get 1.05. Multiply 36,750 by 1.05.
There were 38,587.5 kids last year.
3.)Since the discount is 15% off, do 100-15=85. Now, move the decimal over from the percent, and that makes that .85. Now multiply 50x.85. You get 42.5, or $42.50. Now the coupon is 10%, So subtract 100-10, giving you 90. Now move the decimal over. .90. Multiply 42.5 (or 42.50) by .90. You get 38.25. You do have enough money.
4.) Subtract 100-15, giving you 85. Move decimal over from percent. .85.
Now you would multiply .85 times k. B should be the answer.
Answer:
30 < m
The solution would be (30, ∞)
Explanation:
For company A:
The charge is: $96 for any number of mileage ..............> I
For company B:
The charge is $75 fixed and 0.7 for each mileage m. This means that the charge is: 75 + 0.7m .................> II
We want the charge of company A to be less than the charge of company B. This means that we want I to be less than II.
Therefore,
96 < 75 + 0.7m
96 - 75 < 0.7m
21 < 0.7m
21/0.7 < m
30 < m
This means that for any mileage greater than 30, the charge of company A will be less than the charge of company B
Hope this helps :)
Answer:
b = 6√15
Step-by-step explanation:
6² + b² = 24²
36 + b² = 576
b² = 540
b = √540
b = √9 · √60
b = 3 · √60
b = 3 · √4 · √15
b = 6 √15
