10 tens - 1 ten 1 tenth

How do you find the value of c that satisfy the equation:

victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

Step(i):-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

Mean Value theorem

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

$f^{l} (c) = \frac{f(b) -f(a)}{b-a}$

Step(ii):-

Given f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

f¹(x) = 4(2x) +4(1) = 8x+4

Step(iii):-

By using mean value theorem

$f^{l} (c) = \frac{f(0) -f(-1)}{0-(-1)}$

$8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}$

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

$c = \frac{-4}{8} = \frac{-1}{2} = -0.5$

c ∈ (-1,0)

Conclusion:-

The value of c = -0.5∈ (-1,0)

8 0

3 years ago

Find the missing value so that the line passing through the points has the given slope.

galben [10]

Answer:

11

Step-by-step explanation:

4-1=3/11-7=4

7 0

3 years ago

Ruby started off her savings account with $100, and $0 in her checking account. She made $95 washing dishes and deposited it int

jarptica [38.1K]

Answer:

150+93=241

Step-by-step explanation:

I'm not sure if this is correct but i guess because she got 95 and deposited it into her checking she has 95 and judging on if she spent 2 dollars from her savings or checking i assumed it was savings which leaves it with 148 from 100 after depositing 50 - 2 = 148 so basically

edit: nvm i saw the note now im sure but something i dont understand is that if she made 95 how come the answer choices dont say 93 in checking so im guessing you meant 150+43=193

193 is your answer sorry lol took me a while to work this out or Answer choice C

5 0

3 years ago

Read 2 more answers

Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about 6.9. Use the criterion tha

zavuch27 [327]

Answer:

120 has a z-score higher than 2.5. So yes, it would be unusual to have more than 120 successes out of 200 trials.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$\mu = 80, \sigma = 6.9$

Use the criterion that it is unusual to have data values more than 2.5 standard deviations above the mean or 2.5 standard deviations below the mean

This means that z-scores higher than 2.5 or lower than -2.5 are considered unusual.

Would it be unusual to have more than 120 successes out of 200 trials

We have to find the Z-score of X = 120.

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{120 - 80}{6.9}$