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2 years ago

10 tens - 1 ten 1 tenth

Mathematics

1 answer:

Ann [662]2 years ago

3 0

1 tens cause 1 ten plus one 1 tenth is 11 and 11-10 is 1 right

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Write 2% as a reduced fraction

ANTONII [103]

2% as a reduced fraction is 2/100 = 1/50

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3 years ago

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1) stacey is selling tickets to the school play the tickets are $8 for adults and $5 for children . she sell twice as many ticke

Lapatulllka [165]

2) 25/48 All you do is multiply both.
1) she sold 5 children and 10 adult. 5 *5 equals 25. You double 5 to get twice as many tickets for adults and get 10. 8 *10 equals 80. 80 + 25= $105

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2 years ago

Which is the equation of a line that has a slope ot 1/2 and passes through the point 2, -3

mamaluj [8]

Answer:

y=1/2x-4

Step-by-step explanation:

You are given the slope, 1/2. So you can plug it into the equation (y=mx+b)

You also need to plug in the x and y coordinate your given so you'll have

-3=1/2(2)+b. Then you solve for b, which is -4. You now have your answer, y=1/2x-4.

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2 years ago

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Rephrase in contrapositive form:

miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement $p \rightarrow q$ or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. $\sim q \rightarrow \sim p$

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.

Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"

The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

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2 years ago

Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
$\dfrac{1-\cos x}2=1-\cos^2x$
$1-\cos x=2-2\cos^2x$
$2\cos^2x-\cos x-1=0$
$(2\cos x+1)(\cos x-1)=0$
$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .

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3 years ago