All categories

4 years ago

Factor 2x^2-128 completely

1 answer:

8 0

2x² - 128

2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]

2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)

You might be interested in

Rationalize the denominator.

AlekseyPX

Hello and Good Morning/Afternoon!

Let's take this problem step-by-step:

What the problem asks for:

⇒ to rationalize the denominator

⇒ rationalize means that you multiply the numerator and

demonimator by the denominator

Let's put that into action:

$\frac{\sqrt{a +1}-2 }{\sqrt{a+1}+2 } * \frac{\sqrt{a +1}+2 }{\sqrt{a+1}+2 }\\=\frac{a +1-4 }{a+1+4\sqrt{a+1}+4 } \\=\frac{a-3}{a+4\sqrt{a+1}+5 }$ <== Answer

Hopefully that helps!

4 0

2 years ago

Question Help

Murljashka [212]

Answer:

b and a

Step-by-step explanation:

6 0

3 years ago

Laura determined the difference between 8 and –2 using the additive inverse. Her steps are shown below.

NNADVOKAT [17]

Answer: The 8 should have remained positive.

6 0

2 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!

marshall27 [118]

Answer:

Step-by-step explanation:

I took the quiz :)

4 0

3 years ago

Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ

marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0

4 years ago