Question

Factor 2x^2-128 completely

Answer 1

2x² - 128

2(x² - 64), but (x² - 64)  = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]

2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)