3 years ago

Factor 2x^2-128 completely

1 answer:

8 0

2x² - 128

2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]

2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)

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The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are $n^3t^2$ and $nt^4$ .

The factored form of each term is

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To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

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The LCM of given terms is $n^3t^4$ . Therefore the correct option is C.

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