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lawyer [7]
2 years ago
14

Consider a collection of envelopes consisting of 3 red ​, 3 blue ​, 1 green ​, and 2yellow . If three envelopes are selected at​

random, without​ replacement, determine the probability that at least one envelope is a red envelope.
Mathematics
1 answer:
nevsk [136]2 years ago
4 0

Answer:

The probability is 31/35

Step-by-step explanation:

You might be interested in
find the value of solid figure not including hole cutout. Round to two decimal places. Cube figure is 12 feet long with 4 ft cut
Artemon [7]

Answer:

1577.20 ft³

Step-by-step explanation:

Cube of length = 12 ft = a

Hole diameter which is cutout = 4 ft = d

Hole radius which is cutout = 4/2 =2 ft = r

Volume of the cube = a³

⇒Volume of the cube = a×a×a

⇒Volume of the cube = 12×12×12

⇒Volume of the cube = 1728 ft³

The hole cut out will be in the shape of a cylinder

Volume of cylinder = πr²h

⇒Volume of cylinder = π×2²×12

⇒Volume of cylinder = 150.79 ft³

Now volume of the solid figure with hole cut out is

Volume of the cube - Volume of cylinder

=1728 - 150.79

=1577.20 ft³

∴ Volume of solid figure not including hole cutout is 1577.20 ft³

5 0
3 years ago
The fastest speed recorded for a runner is 27 mph. This is 20%of the fastest speed for a water skier. Find the record for a wate
posledela
The answer is 135 mph

6 0
3 years ago
If x-1/x=5 find x^3+1/x^3=?
ipn [44]

\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126

5 0
3 years ago
Read 2 more answers
Can someone answer this for me im really bad at math 6x+17
Maslowich

Answer:

It cannot be answered if we don't figure out what x means. IF we knew what X is we can multiply 6 by x and then add 7.

an example would be if x was 3. we could figure out the answer by just doing (6*3)+7=25

7 0
2 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

  • \angle DIH\cong \angle EGH as alternate interior angles;
  • \angle DHI\cong \angle GHE as vertical angles;
  • DH\cong HE because point H bisects segment DE (given).

Thus,

\triangle DIH\cong \triangle EGH by AAS postulate

4 0
3 years ago
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