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Andrews [41]
3 years ago
8

The ratio of the number of cups of yellow paint to the number of cups of blue paint that Greg mixed to make a shade of green pai

nt is 2:1.
Part A: Write a sentence to describe the number of cups of yellow paint that Greg mixed with each cup of blue paint.

Part B: How many cups of blue paint should Greg add to each cup of yellow paint to make the shade of green? Explain your reasoning.

Part C: If Greg purchased 6 cups of yellow paint for $54, what is the unit price per cup of yellow paint?
Mathematics
1 answer:
Greeley [361]3 years ago
5 0

why did you delete my answer it was right like if I'm going to waste my time on trying to help you and you delete it that's not ok cause I worked hard on it and it was 100% right so you can stop deleting my answers when I'm wasting my time on you

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ANSWER THIS QUESTION ABOUT DENSITY<3
Vinvika [58]

Answer:

25/36 cm^3

0.69444... g/cm^3

Step-by-step explanation:

Find volume of cube: 4*12*3

144 cm^3

Rember the density formula: g/cm^3

subsitute:

100g/144cm^3

simplified 24/36 cm^3

0.69444... g/cm^3

3 0
4 years ago
A video merchant sold 24 cases of tapes, which was 20% of what he had left. What percent of tapes did he sell?
Naddika [18.5K]

Answer:

16.67% of cases of tapes were sold.

Step-by-step explanation:

We are given the following in the question:

Number of cases of tapes sold = 24

Thus is 20% of tapes left.

Let x be the total number of tapes left.

Thus, we can write:

20\%\rimes x = 24\\\\\dfrac{20}{100}\times x = 24\\\\x = 24\times 5 = 120

Thus, total number of tapes =

=24 + 120 = 144

Percentage of tapes sold  =

=\dfrac{24}{144}\times 100\% = 16.67\%

Thus, 16.67% of cases of tapes were sold.

3 0
4 years ago
Which one is it for the answer
snow_lady [41]

10*10*10*10*10*7867 equal 786700100

8 0
3 years ago
Read 2 more answers
Which of the following terms are considered like terms? Select all that apply. (more than one)
IRISSAK [1]

Answer:

maybe 3x

Step-by-step explanation:

3 0
3 years ago
I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0
2 years ago
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