2/10ths of an hour. You do 12/60 and get 0.2
A. After the mod. One wall is “x” longer than original (horizontal in diagram) and the other is “x” shorter (vertical)
(30+x)(30-x)
b. He original area = 30 x 30 = 900 sq. ft.
The mod. Area is (30+6)(30-6) = 36x24= 764 sq. ft.
So the room was largest to begin with when it was a square
I believe it is 10 to the power of negative 7
<span>length = L
</span>width = w
L = (5w-2) cm
width = 2 cm
length = 5w-2 = 5*2-2 = 8 cm
Answer: The hypotenuse is 53 (approximately)
Step-by-step explanation: In this question we shall apply the Pythagoras theorem which states that;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse and AB and BC are the two other sides. Having been given that the two other sides are 36 and 39 units respectively, the hypotenuse is now,
AC^2 = 36^2 + 39^2
AC^2 = 1296 + 1521
AC^2 = 2817
Add the square root sign to both sides of the equation
AC = 53.0754
Therefore the hypotenuse is approximately 53 units.
