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kramer
3 years ago
10

What is the answer please

Mathematics
2 answers:
USPshnik [31]3 years ago
6 0

Answer:

≈ 20

Step-by-step explanation:

2.65 ≈ 3 ( to 1 significant figure )

4.1758 ≈ 4 ( to 1 significant figure )

7.917 ≈ 8 ( to 1 significant figure )

Then approximate calculation is

3 × 4 + 8 = 12 + 8 = 20

Daniel [21]3 years ago
4 0

Answer:

the process by which green plants turn carbon dioxide and water into food using energy from sunlight

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It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat
ella [17]
Hi, thank you for posting your question here at Brainly.

All you have to do to acquire the equation is to substitute the variables to the formula for A and simplify. Since A = 1/2*b*h and h = bsin(C), then A can be in terms of one variable only, which is b.

A = 1/2*b*bsin(c)
A = 1/2*b^2*sin(C)
4 0
3 years ago
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Write an equation in point-slope form of the line that passes through (7, -6) and has the slope m=12.
Goshia [24]

Answer:

Step-by-step explanation:

y + 6 = 12(x - 7)

y + 6 = 12x - 84

y = 12x - 90

6 0
3 years ago
ZA and ZB are supplementary angles. If m_A
KatRina [158]

Answer:

∠A = 107

∠B = 73

Step-by-step explanation:

∠A ,  ∠B are supplementary. So, ∠A + ∠B = 180

5x + 27 + 5x - 7 = 180

5x + 5x  + 27 - 7 = 180       {Combine like terms}

             10x + 20=180

                    10x = 180 -20

                   10x = 160

                      x = 160/10

x = 16

∠A = 5x + 27 = 5*16 + 27 = 80 + 27 = 107

∠B = 5x - 7 = 5*16 - 7 = 80 - 7 = 73

5 0
3 years ago
The drama club was selling tickets
Lubov Fominskaja [6]

Answer:

108 student tickets, and 176 adult tickets  were sold

Step-by-step explanation:

Adult ticket $8  Call the number of adult tickets sold "a"

Student ticket $5  Call the number of student tickets sold "s"

Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284

Then we create two different equations with the information given:

a + s = 284

8 * a + 5 * s = 1948

we can solve for s in the first equation as follows: s = 284 - a

and use it in the second equation

8 a + 5 (284 - a) = 1948

8 a + 1420 - 5 a = 1948

combining

3 a = 528

a = 528/3

a = 176

we find the number of student tickets using this answer in the substitution equation we used:

s - 284 - 176 = 108

Therefore 108 student tickets, and 176 adult tickets  were sold.

5 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.
Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Step-by-step explanation:

GIven that:

f(x) = 5e^{-x^2} cos (4x)

The Maclaurin series of cos x can be expressed as :

\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+...  \ \ \ (1)}

\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0}  \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!}  -\dfrac{x^6}{3!}+... \ \ \  (2)}

From equation(1), substituting x with (4x), Then:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}

The first three terms of cos (4x) is:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}

\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}

\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}

Multiplying equation (2) with (3); we have :

\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }

\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Finally , multiplying 5 with \mathtt{ e^{-x^2} cos (4x) } ; we have:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

7 0
3 years ago
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