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zzz [600]
3 years ago
14

According to the number line, which statement MUST be true? A) A < 0 B) B > 10 C) C < 15 D) D > 15

Mathematics
2 answers:
Elena L [17]3 years ago
6 0

According to the number line, the statement that MUST be true- is (C) C < 15

<u>c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true</u>

<u></u>

<u></u>

<u>Step-by-step explanation:</u>

As you know, in the number line we are looking at the roots of the numbers, and as you know; (√A)^2 = A, so using this, we can analyze each option:

a) A can not be less than zero, because √A is bigger than zero.

b) we can see that √B is smaller than 3, and 3^2 = 9, so B must be smaller than 9, and then, smaller than 10.

<u>c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true</u>

d) we can see that √D is bigger than 4, and using the same reasoning as before, we can see that D is bigger than 16, and 16 is bigger than 15, so D > 15 is false

iris [78.8K]3 years ago
6 0

Answer:

There is no number line so i cant answer that

Step-by-step explanation:

sorry

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Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$
Nana76 [90]

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

4 0
4 years ago
What is the domain of f(x)?
Varvara68 [4.7K]

Answer:

Step-by-step explanation:Domain is the set of x values in which the function exists. Range is the set of y values in which the function exists. f(x) = 8 / (x + 9) Since the denominator cannot be zero, we set the denominator equal to zero.

7 0
3 years ago
Consider the quadratic expression given below.
Jlenok [28]
3 x^{2} -30x-72=3( x^{2} -10x-24)

Using cross multiplication method,

x                         -12       -12x

x                             2          2x  

x^{2}                        -24        -10x

Therefore, 
3 x^{2} -30x-72=3( x^{2} -10x-24)
                               =3(x-12)(x+2)
5 0
4 years ago
Read 2 more answers
Can someone please help me find the domain, range, intercepts, and asymptotes pf this function?
marishachu [46]
1) given function

y = - 2 ^ ( -x + 2) + 1

2) domain: domain is the set of the x-values for which the function is defined.

The exponential function is defined for all the real numbers, so the domain of the given function is all the real numbers.

3) x-intercept => y = 0

=> y = - 2 ^ ( -x + 2) + 1 = 0 => 2^ ( -x + 2) = 1

=> - x + 2 = 0 => x = 2

The x-intercept is x = 0

4) y-intercept => x = 0

=> y = - 2 ^ ( -x + 2) + 1= - 2 ^ ( 0 + 2)  1 = - (2)^(2) + 1 =- 4 + 1 = - 3

=> The y-intercept is - 3

5) limit when x -> negative infinite

Lim f(x) when x -> ∞ = - ∞

6) limit when x -> infinite

Lim f(x) when x - > infinite = 1

=> asymptote = y = 1

7) range is the set of values of the fucntion: y

Given that the function is strictly decreasing from -∞ to ∞, the range is from - ∞ to less than 1

Range (-∞,1)


3 0
3 years ago
Please helppp quickly
miskamm [114]

Answer:

x=-12

Step-by-step explanation:

I did it in my head.

8 0
3 years ago
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