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3 years ago

According to the number line, which statement MUST be true? A) A < 0 B) B > 10 C) C < 15 D) D > 15

Mathematics

2 answers:

Elena L [17]3 years ago

6 0

According to the number line, the statement that MUST be true- is (C) C < 15

c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true

Step-by-step explanation:

As you know, in the number line we are looking at the roots of the numbers, and as you know; (√A)^2 = A, so using this, we can analyze each option:

a) A can not be less than zero, because √A is bigger than zero.

b) we can see that √B is smaller than 3, and 3^2 = 9, so B must be smaller than 9, and then, smaller than 10.

c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true

d) we can see that √D is bigger than 4, and using the same reasoning as before, we can see that D is bigger than 16, and 16 is bigger than 15, so D > 15 is false

iris [78.8K]3 years ago

6 0

Answer:

There is no number line so i cant answer that

Step-by-step explanation:

sorry

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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27.

padilas [110]

Answer:

Step-by-step explanation:

The IQR is quartile 3 - quartile 1. First, we need to find the mean of the dataset, which is 50 -- the fifth number. Then, the median of the dataset on the left of the fifth number is the first quartile, and the median of the dataset on the right is the third. We get Q1 to then be halfway between 30 and 50, or 40, and Q3 to be halfway between 56 and n, so Q3 = (56+n)/2. Since we need Q3-Q1=27, or (56+n)/2-40=27, we have (56+n)/2=67 and 56+n=134, so n = 134-56=78

3 0

3 years ago

Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ

marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0

3 years ago

Need help finding the value of x and y

kap26 [50]

Answer:

The values of x = 12 and y = 8.

Step-by-step explanation:

From the given figure ,

ΔMTW≅ΔBGK

That is, these two triangles are congruent.

If two triangles are congruent , all the corresponding angles and corresponding sides are equal.

Congruency is different from similarity . Similarity means two triangles which are the same with different dimensions.

Therefore , ∠MTW = ∠BGK

(4x - 3)° = 45°

4x = 48°

x = 12

Since ∠MTW = 45° ,

∠TMW = 180 - (41 +45)

= 180 - 86

=94°

From congruency ,

∠TMW = ∠GBK

94° = 11y + 6

11y = 88°

y = 8

4 0

3 years ago

Does anyone know how to do this ?

Pavel [41]

I believe you go to the spots on the graph and then just found up from there, and do that with every point

6 0

3 years ago

If the class mark and class size of the class

Gemiola [76]

Answer:

The class interval is: 20-30

Step-by-step explanation:

Let l be the lower class limit and u be the upper class limit.

Then according to given statement that class mark is 25

$\frac{l+u}{2} = 25\\l+u = 50\ \ \ Eqn\ 1$

And

Class size is 10

So, the second equation will be:

$u-l = 10\ \ \ \ Eqn\ 2$

Adding equation 1 and 2

$l+u+u-l = 50+10\\2u = 60\\\frac{2u}{2} = \frac{60}{2}\\u = 30$

Now putting u =30 in equation 1

$l+u = 50\\l+30 = 50\\l = 50-30\\l = 20$

A class interval is written in the form that lower limit comes first and upper limit comes second.

So,

20-30

Hence,

The class interval is: 20-30

7 0

3 years ago