Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
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* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
Answer:
i think the answer is A
Step-by-step explanation:
again "i think". so i could be wrong
$10.13
4 1/2=4.5
4.5x2.25=10.125
10.125 rounds to 10.13
Answer:
No, it's not equivalent
Step-by-step explanation:
Try and solve the one with the bracket first. Expand 8(15-r) : 8x15 and 8x-r = 120 - 8r
Therefore, the equation can now be written as:
6r-r + 120-8r + 23-6
Rearrange the like terms together and solve the equation:
6r-r-8r + 120+23-6 = -3r + 137
