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Marysya12 [62]
2 years ago
8

Does somebody knows how to do this?

Mathematics
1 answer:
MrMuchimi2 years ago
5 0

Answer:

Area of the triangle = 6x3/2=18/2=9cm²

now find semicircle then add

area of the semicircle= πr²/2=π6²/2=36π/2=18π

now add and you get

Area of the region = (18π+9)cm²

Step-by-step explanation:

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\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

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Read 2 more answers
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