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MrMuchimi
3 years ago
6

How much coffee will each person get if 3 people share 1/2 a pound of coffee?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:6 pounds you need to divide 3 by .5 and you will get 5

Step-by-step explanation:

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How old am I if 400 reduced by 3 times my age is 241? Can I please have an explanation..
OLEGan [10]

Given :

400 reduced by 3 times my age is 241

To Find :

My age .

Solution :

Let, age is x .

So , expressing given condition mathematically , we get :

400-3x=241\\\\3x=400-241\\\\3x=159\\\\x = 53

Therefore, the age is 53 years.

Hence, this is the required solution.

7 0
3 years ago
X+4 over<br> x^2−5x+6<br> ÷ <br> x^2−16 over<br> x+3
Amiraneli [1.4K]

Answer:

x+3 over (x-3)(x-2)(x-4)

8 0
3 years ago
Can anyone help me with this??
Rudiy27
I think that’s the answer

4 0
3 years ago
Read 2 more answers
△STR≅△LMN, SR=7b+8, and LN=11b−12. Find b and SR.
Goryan [66]

Given:

\Delta STR\cong \Delta LMN

SR=7b+8

LN=11b-12

To find:

The value of b and SR.

Solution:

We have,

\Delta STR\cong \Delta LMN                          (Given)

ST\cong LN                                  (CPCTC)

ST=LN

Substituting the given values, we get

7b+8=11b-12

7b-11b=-8-12

-4b=-20

Divide both sides by -4.

\dfrac{-4b}{-4}=\dfrac{-20}{-4}

b=5

Now,

SR=7b+8

SR=7(5)+8

SR=35+8

SR=43

Therefore, the value of b is 5 and the measure of SR is 43 units.

6 0
3 years ago
What is the greatest value in the range of f(x) = x^2 - 3 for the domain (-3,0,1,2)
bezimeni [28]

Answer:

f(-3)=6 is the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2)

Step-by-step explanation:

Given that the function f is defined for range by f(x)=x^2-3 for the domain (-3,0,1,2)

To find the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2):

f(x)=x^2-3 for the domain (-3,0,1,2)

That is put x=-3 in the given function f(x)=x^2-3 we get

f(-3)=(-3)^2-3

=3^2-3

=9-3

=6

Therefore f(-3)=6

put x=0 in the given function f(x)=x^2-3 we get

f(0)=(0)^2-3

=0-3

=-3

Therefore f(0)=-3

put x=1 in the given function f(x)=x^2-3 we get

f(1)=(1)^2-3

=1-3

=-2

Therefore f(1)=-2

put x=-3 in the given function f(x)=x^2-3 we get

f(2)=(2)^2-3

=4-3

=1

Therefore f(2)=1

Comparing the values of f(-3)=6,f(0)=-3,f(1)=-2,and f(2)=1 to find the greatest value in the range of f(x) = x^2 - 3 for the domain (-3,0,1,2) we get

Therefore f(-3)=6 is the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2)

8 0
3 years ago
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