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Veseljchak [2.6K]
3 years ago
7

Which relation is a function? A. {(8,3), (-1,-1), (8,7), (-1,7)} B. {(1,6), (2,-3), (2,7), (3,7)} C. {(-3,6), (-3,9), (-1,4), (0

,3)} D. {(4,7), (-9,3), (0,3), (2,2)}
Mathematics
1 answer:
frez [133]3 years ago
6 0

A. Not a function since x = 8 repeats. We have x = 8 pair up with y = 3 and y = 7 at the same time.

B. Not a function for similar reasons. Now x = 2 repeats. We have x = 2 pair up with y = -3 and y = 7

C. Not a function. We have x = -3 pair up with both y = 6 and y = 9 at the same time.

D. This is a function. Each x value is listed once and only once. Any input (x) leads to exactly one output (y). For choices A through C, it is possible to draw a vertical line through more than one point, thereby failing the vertical line test. In choice D, it is not possible to draw a vertical line through more than one point of this list. So this relation passes the vertical line test.

Answer: Choice D

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If RX=4 and XS=9, then XT=<br> And how do you get it?
konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

RS^2=RT^2+TS^2

we have

RS=RX+XS=4+9=13\ units ---> by segment addition postulate

substitute

RT^2+TS^2=169  ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

RT^2=RX^2+XT^2

we have

RX=4\ units

substitute

RT^2=4^2+XT^2

RT^2=16+XT^2

XT^2=RT^2-16 ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

TS^2=XS^2+XT^2

we have

XS=9\ units

substitute

TS^2=9^2+XT^2

TS^2=81+XT^2

XT^2=TS^2-81 ----> equation C

step 4

equate equation B and equation C

TS^2-81=RT^2-16

TS^2-RT^2=81-16

TS^2-RT^2=65 ----> equation D

step 5

Solve the system

RT^2+TS^2=169 ----> equation A

TS^2-RT^2=65 ----> equation D

Solve by elimination

Adds equation A and equation D

RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117

Find the value of  RT^2

RT^2+117=169\\RT^2=52

step 6

Find the value of XT

equation C

XT^2=117-81\\XT^2=36\\XT=6\ units

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Step-by-step explanation:

Once you know that just multiply like normal nothing to it.

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