This is a 30-60-90 triangle and we can apply rules to easily identify the hypotenuse of this triangle, which is denoted by <em>x</em>.
The length of the longer side of the triangle is given in the problem. To solve the hypotenuse of this triangle, let's solve first for the length of the shorter side of the triangle.
The shorter side can be solved by just dividing the length of the longer side by the square root of 3. Hence, we have
![short=\frac{4}{\sqrt[]{3}}](https://tex.z-dn.net/?f=short%3D%5Cfrac%7B4%7D%7B%5Csqrt%5B%5D%7B3%7D%7D)
Since we already have the values for the length of the shorter side and longer side, we can solve for the hypotenuse using the Pythagorean theorem.
![\begin{gathered} c=\sqrt[]{a^2+b^2} \\ c=\sqrt[]{4^2+(\frac{4}{\sqrt[]{3}})^2} \\ c=\sqrt[]{16+\frac{16}{3}} \\ c=\sqrt[]{\frac{64}{3}} \\ c=\frac{8}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}} \\ c=\frac{8\sqrt[]{3}}{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%3D%5Csqrt%5B%5D%7Ba%5E2%2Bb%5E2%7D%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B4%5E2%2B%28%5Cfrac%7B4%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%29%5E2%7D%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B16%2B%5Cfrac%7B16%7D%7B3%7D%7D%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B%5Cfrac%7B64%7D%7B3%7D%7D%20%5C%5C%20c%3D%5Cfrac%7B8%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%5Ccdot%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%20c%3D%5Cfrac%7B8%5Csqrt%5B%5D%7B3%7D%7D%7B3%7D%20%5Cend%7Bgathered%7D)
Hence, the value of hypotenuse for this right triangle is
![x=\frac{8\sqrt[]{3}}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%5Csqrt%5B%5D%7B3%7D%7D%7B3%7D)
Answer:
28 Days
Step-by-step explanation:
35 divided by 1.25 is 28
Answer:
5 = a whole big mac right so if you get a triple big mac divide the big mac to the other one
Step-by-step explanation:
Step-by-step explanation:
According to PEMDAS parentheses are first.
2(6+1) can be simplified to 12+2.
5(3+2) can be simplified to 15+10
Add these two together.
12+2+15+10
14+15+10
29+10
y=39
Note - when you have something like this in math 2(6+1) it means you need to do 2 x 6 and 2 x 1
Answer:
1
Step-by-step explanation:
Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.
The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.
The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19
The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19
The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is
P(apple or peach or orange) = P(apple) + P(peach) + P(orange)
= 5/19 + 9/19 + 5/19
= (5 + 9 + 5)/19
= 19/19
= 1
