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Aneli [31]
3 years ago
6

Problem Set 100 yd. =

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

1 yard = 3 feet

We can re-write this by dividing both sides by yards or feet to get

1 = 3 feet / 1 yard

or

1 yard / 3 feet = 1

Since we're solving for feet we want yards to cancel, so use the top proportion

(3 feet / 1 yard)(100 yards) = 300 feet / 1 = 300 feet

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Find the percent decrease. Round to the nearest percent.<br><br><br> From 90°F to 70°F
Goryan [66]

Answer:

22

Step-by-step explanation:

90*x = 70

x = 7/9

x = 78%

100-78 = 22

3 0
3 years ago
What is the missing number in the sequence below?<br><br> 39, 24, 9, ____, -21
Oksi-84 [34.3K]

Answer:

-6

Step-by-step explanation:

The pattern here is that you substract 15 every time you move a number (left to right) , therefore: 9-15 = -6

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)

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Esme buys jacketsfor 500 each and prices them for 700 each.If the selling price is reduced by 20%. how much profitdoes Esme make
Blababa [14]

Answer:

($) 60 is the profit per item when the selling price is reduced by 20%

Step-by-step explanation: 20% of 700 is 140.

The original profit is 700 - 500 = 200. The selling price is 140 less, Subtract 140 from 200. That leaves a profit of 60. (Not necessarily dollars, as the currency was not given in the question.)

7 0
3 years ago
Question 4 of 15<br> Which of the following is not a polynomial?
aleksklad [387]

Answer:a

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A scientist measure change in the temperature of chemical solution at the start of the experiment , the solutions is at temperat
zhannawk [14.2K]

Answer:

The temperature of the chemical solution after t hours is -14.96-2.9t\;^{\circ}C

Step-by-step explanation:

Given that the initial temperature of the chemical solution, T_0= -14.96^{\circ}C.

The rate of decreasing temperature, R = 2.9^{\circ}C/ hour

So, after t hours, the temperature of the chemical solution will decrease by Rt=2.9t^{\circ}C.

So, the temperature of the chemical solution after t hours,

T=T_0-Rt \\\\\Rightarrow T = -14.96-2.9t\;^{\circ}C

Hence, the temperature of the chemical solution after t hours is -14.96-2.9t^{\circ}C.

4 0
3 years ago
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