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3 years ago

7

The hover dam contains 3 1/2 millon cubic yards of concrete.The grand coulee dam contains 2 1/2 times as much. How much concrete

does the grand coulee dam contain

1 answer:

Margarita [4]3 years ago

8 0

grand coulee dam (g) contains 2.5 times as much concrete as the hover dam (h)

Therefore,

g = 2.5 * h

h = 3.5 million

g = 2.5 * 3.5

g = 8.75 million yards of concrete

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Each leg of a 45-45-90 triangle has a length of 6 units. What is the length of its hypotenuse?

andreyandreev [35.5K]

Use the Pythagorean theorem:
$(\hbox{one leg})^2+(\hbox{the other leg})^2=(\hbox{hypotenuse})^2 \\
6^2+6^2=x^2 \\
6^2 \times 2=x^2 \\
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$

The length of the hypotenuse is 6√2 units.

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3 years ago

What is the slope of the graph y = -25x - 42?

sweet [91]

-25x is the slope
-42 is the y-intercept

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2 years ago

Read 2 more answers

Give 1 pair of Vertical and 1 pair of Supplementary angles

mojhsa [17]

Solution:

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These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

$\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}$

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

$\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}$

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0

1 year ago

∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len

leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

<u>AB</u>

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07$

<u />

<u>BC</u>

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06$

<u />

<u>AC</u>

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04$

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2 years ago

Write the equatoin of a graph that has Roots of x={-2,0,4} and has a point of (-1,10)

zheka24 [161]

Step-by-step explanation:

to have "roots" means that the function delivers 0 as function result for these values of x.

so,

f(x) = 0 for x = -2, x = 0 and x = 4

we can build this function as a product of factors.

each factor is an expression of x that turns 0 for the given value of x.

what is the simplest expression of x that turns 0, when x = -2 ?

well : x + 2

as you can easily see, this is 0, when x = -2.

and the easiest existing of x that is 0, when x = 0 ?

totally simple : just x.

and then x - 4 for x = 4

so, our function is

f(x) = x(x + 2)(x - 4)

but : this is one of infinite possibilities.

let's see what happens, if we use the x coordinate (-1) of the given point (-1, 10).

we know, the result must be 10.

-1×(-1 + 2)(-1 - 4) = -1×1×-5 = 5

aha ! so, in order to get 10 instead of just 5 we must multiply the whole thing by 2.

as n×0 is always still 0, this does not change our 0 points (or roots).

so, our full function is :

f(x) = 2x(x + 2)(x - 4)

or, if you need the function as a polynomial, we need to do the multiplications :

f(x) = 2x(x² - 4x + 2x - 8) = 2x(x² - 2x - 8) = 2x³ - 4x² - 16x

3 0

2 years ago