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Leto [7]
3 years ago
10

The length of a rectangle is six times its width. If the perimeter of the rectangle is 98 yd , find its area.

Mathematics
1 answer:
kumpel [21]3 years ago
4 0
P=2(W + L)
p= 2W + 2L
98=2W + 2(6W)
98=2W + 12W
98=W
98/14=14W/14
W=7

L= 6W
L = 6(7)
L= 42

CHECK
p=2(7 +42)
p=2(49)
p= 98

Area of a rectangle = W X L
Area of a rectangle = 7 X 42
Area of a rectangle = 294
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The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

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Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
Read 2 more answers
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