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NeTakaya
3 years ago
6

−

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer: =296

Step-by-step explanation: −2*4=-8+20=28*3=84+48=132*2=164−2=162*4+20*3+48*2= 296

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Measure of angle ABD =5x, measure of angle DBC =3x+10 solve for x and find measure of angle ABC
Lelechka [254]
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6 0
4 years ago
Lionel is planning a one-day outing.
vaieri [72.5K]

For this case, the first thing we must do is define variables.

We have then:

x: number of rides

y: total cost

We now write the equations for each park.

For The Thrill amusement park:

y = 5x + 40

For The Splash water park:

y = 3x + 60

Answer:

A system of equations that could be used to determine the solution where the cost per ride of the two amusement parks, and, is the same is:

y = 5x + 40

y = 3x + 60

6 0
3 years ago
Can someone help? If b/a=c/b=d/c=2/3, find a:b:c:d.
blagie [28]

Answer: a:b:c:d = 16:24:30:40

You can also divide the ratio by 2 because all terms have 2 in common. Which would be  a:b:c:d = 8:12:15:20

8 0
2 years ago
A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a
Sphinxa [80]
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx  dy= \frac{1}{3}k (15-4)^4=4880.33k

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.
7 0
3 years ago
Answer please.....<br> Thanks!!!!
Tems11 [23]
A. x= 11/5
b. x= 6
c. x= -12/2
d. x= 6/5
3 0
3 years ago
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