The model equation for any line is
y = mx + b,
where m is slope and b is y-intercept (where the line intersects the y-axis).
The slope is change in y over change in x. You can find the slope by picking two points. The numerator will be the difference in y-coordinates, and the denominator will be the difference in x-coordinates.
As an equation, this is
slope =

,
where the two points are (x1, y1) and (x2, y2).
Let's pick two points to find the slope: (0, 5) and (3, -7).
The slope is

Now that we have the slope m = -4, we need to find the y-intercept b. The line crosses the y-axis at 5, so b = 5.
The equation is y = -4x + 5
(6x^2+5x+1)/(3x^2+4x+1)
= (3x+1)(2x+1)/(3x+1)(x+1)
= (2x+1)/(x+1)
The first step is to write this equation into general form. The
general form of an equation is:
ax^2 + bx + c = 0
To make this equation to general form, you have to simplify
the equation first.
2/3(x-4) (x+5) = 1
2/3 (x^2 + 5x – 4x – 20) = 1
2/3(x^2 + x -20) = 1
2/3x^2 + 2/3x – 40/3 = 1
2/3x^2 + 2/3x – 40/3 – 1 = 0
2/3x^2 +2/3x – 43/3 = 0
Therefore, a = 2/3 ; b = 2/3 ; c = -43/3
9/56 is already in its simplest form. You CANNOT make it more reduced than this