Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
Answer:
1.792
Step-by-step explanation:
(24,215-23,500)/[3678/sqrt(85)]
715/[3678/sqrt(85)]
715/398.94
1.792
Please give me brainliest :)
Answer: (1,1)
Step-by-step explanation:
Answer:
13.5
Step-by-step explanation:
Round the .45 to .5
![a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6](https://tex.z-dn.net/?f=a%5Ccdot%20a%5Ccdot%20a%3D216%5C%5C%5C%5Ca%5E3%3D216%5Cto%20a%3D%5Csqrt%5B3%5D%7B216%7D%5C%5C%5C%5C%5Cboxed%7Ba%3D6%7D%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20b%5Ccdot%20c%3D52%5C%20%5Ctext%7Bto%20the%20second%20expression%7D%5C%20a%5Ccdot%20b%5Ccdot%20c%3D96%3A%5C%5C%5C%5Cabc96%5C%20%5Cwedge%5C%20bc%3D52%5Cto%20a%2852%29%3D96%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%2052%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B96%7D%7B52%7D%5Cto%20a%3D%5Cdfrac%7B24%7D%7B13%7D%5Cneq6)
a = 6 and a = 24/13 FALSE!!!
<h3>Answer: NO SOLUTION.</h3>