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kodGreya [7K]
3 years ago
11

Recall that an integer 'd' is said to be a divisor of an integer 'a', if 'a/d' is also an integer. For how many integers 'a' bet

ween -200 and -1 inclusive is the product of the divisors of a negative?
Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:

The integers are -1,-2,-4,-5,-8,-10,-20,-25,-40,-50,-100,-200

Step-by-step explanation:

Step1. To get negative integers between -200 and -1, obtain the factors of -200,that is negative numbers that can divide -200 without a remainder. Whatever negative number that can divide -200 are the required integers.

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Brrunno [24]

Answer:

B 41.4

Step-by-step explanation:

complete Pythagoras for general triangles :

c² = a² + b² - 2ab×cos(C)

with "c" being the side opposite of the angle C.

=>

8² = 10² + 12² - 2×10×12×cos(C)

64 = 244 - 240×cos(C)

240×cos(C) = 244 - 64 = 180

cos(C) = 180/240 = 18/24 = 3/4 = 0.75

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5 0
3 years ago
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SpyIntel [72]
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3 years ago
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lorasvet [3.4K]

Answer:

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5 0
3 years ago
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Neporo4naja [7]
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6 0
3 years ago
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AysviL [449]

Answer:

6

Step-by-step explanation:

Step 1:

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