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lidiya [134]
3 years ago
6

How do you write 331 in scientific notation?

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0
<span>scientific notation: 
</span>331 = 3.31 x 10²
meriva3 years ago
3 0
Hello,

The answer is "<span>3.31*10^2".</span>

Reason:

331=331*10^3

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
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A helicopter takes off from the ground 800 feet from the base of a building. It flies in a straight line directly to the top of
Stolb23 [73]

Answer:

11.3°

Step-by-step explanation:

Refer the attached figure .

Height of building i.e. AB = 160 feet.

A helicopter takes off from the ground 800 feet from the base of a building i.e. BC = 800 ft.

We are required to find what angle did the helicopter take off from i.e. ∠ACB

We will use trigonometric ratio .

tan\theta = \frac{Perpendicular}{Base}

tan\theta = \frac{AB}{BC}

tan\theta = \frac{160}{800}

tan\theta = \frac{1}{5}

tan\theta = 0.2

\theta =tan^{-1} 0.2

\theta =11.3^{\circ}

Thus the  angle at which  the helicopter take off from is 11.3°

3 0
4 years ago
The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (−1, 8). The ball reach
sukhopar [10]

Answer:

The required equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

Explanation:

Let us assume that the hole is at y = 0m, with x as the time.

From the question we have (-1s, 8m) as the vertex (here x being the time variable is supposed to be in seconds and y being the distance variable is supposed to be in meters)

At x = 1s, the ball gets to the hole, therefore we have point (1s, 0m)

We know that the vertex of the parabola y = ax² + bx + c is at

x =\frac{-b}{2a}

therefore we have:

-1 = \frac{-b}{2a}

We then have the following equations:

8 = a\times -1^2 + b\times -1 + c

0 = a\times -1^2 + b\times 1 + c

-1 = \frac{-b}{2a}

From the 3rd equation we have

1 X 2a = b.

Therefore we have:

8 = a\times -1^2 - 1\times 2a\times1 + c

0 = a\times 1^2 + 1 \times2a\times 1 + c

We can simplify both equations and get:

8 = a\times( -1^2 - 2s^2) + c = -a\times 3^2 + c

0 = a\times(1^2 + 2^2) + c = a\times 3^2 + c

The first equation now becomes:

8 = -a\times 3 - a\times 3 = -a\times 6

a = frac{8}{-6} = -\frac{4}{3}

With a, we can find the values of c and b.

c = -a\times3 = -(-\frac{4}{3})*3 = 4

b = 1\times 2a = 1\times 2(-\frac{4}{3})= -\frac{8}{3}

Then the equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

6 0
3 years ago
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