So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages
notice, Fred is always 40years older than Irene
thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "
now, when is Fred 5 times Irene's age or 5*i or 5i? well,
f = fred's age i = irene's age
f = i + 40
now if f = 5i
5i = i + 40 <--- solve for "i" to see how old Irene was then
We have that
<span>2cscx-3=-5---------> 2cscx=-5+3---------> cscx=-2/2---------> cscx=-1
we know that
csc x=1/sin x
then
1/sin x=-1--------------> sin x=-1
x=arcsin (-1)---------> x=-90</span>°
x=-90°---------------> 360°-90°-----------> x=270°------------> 3pi/2<span>
the answer is
x=3pi/2 radians
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