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3 years ago

I would mark brainlest Please Help With this math

Mathematics

1 answer:

katovenus [111]3 years ago

7 0

Find 6 in the f(y) column.

Find the output next to 6 in the f(y) column.

To find the answer, you basically start from the f(y) column on the right, go straight down to 6, because we are finding f(6), and choose the number that is on the left of 6, which is 4.

☺☺

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Two catalysts may be used in a batch chemical process. Twelve batches were prepared using catalyst 1, resulting in an average yi

aalyn [17]

Answer:

a) $t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

$df=12+15-2=25$

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) $(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

Step-by-step explanation:

Notation and hypothesis

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

Part a

The system of hypothesis on this case are:

Null hypothesis: $\mu_2 \leq \mu_1$

Alternative hypothesis: $\mu_2 > \mu_1$

Or equivalently:

Null hypothesis: $\mu_2 - \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 > 0$

Our notation on this case :

$n_1 =12$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =85$ represent the sample mean for the group 1

$\bar X_2 =91$ represent the sample mean for the group 2

$s_1=3$ represent the sample standard deviation for group 1

$s_2=2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(12-1)(3)^2 +(15 -1)(2)^2}{12 +15 -2}=6.2$

And the deviation would be just the square root of the variance:

$S_p=2.490$

Calculate the statistic

And now we can calculate the statistic:

$t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

Now we can calculate the degrees of freedom given by:

$df=12+15-2=25$

Calculate the p value

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

Conclusion

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

For the 99% of confidence we have $\alpha=1-0.99 = 0.01$ and $\alpha/2 =0.005$ and the critical value with 25 degrees of freedom on the t distribution is $t_{\alpha/2}= 2.79$

And replacing we got:

$(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

7 0

3 years ago

Need answer urgently please will give thanks and mark Brainliest

babymother [125]

Answer:

Step-by-step explanation:

sqrt(7) = about 2.6

and that divided by 2 is

0.8 which means D is the Answer

8 0

3 years ago

What would I have to do here? Somebody please help me! (Look at the bottom problem not the top)

Zinaida [17]

Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer.
I hope this helps.

8 0

3 years ago

Hereeeeeee helllllllpp lol

Ivenika [448]

It should be 0 because the only factor changing is the x value

7 0

3 years ago

Suppose an apple picker in China earns an average wage of 45 cents per hour. An apple picker can harvest about 2.0 bushels of ap

Eduardwww [97]

Answer:

0.0398 dollars

Step-by-step explanation:

We are told in the question that

An apple picker in China earns an average wage of 45 cents per hour.

Mathematically

1 hour= 45 cents............ Equation 1

An apple picker can harvest about 2.0 bushels of apples each hour.

Mathematically

2.0 bushels = 1 hour ..............Equation 2

We are told that each bushel contains about 126 apples

1 bushel = 126 apples

2 bushels =

126 × 2

= 252 apples

Combining Equation 1 and 2 together,

We can say

An apple picker in 1 hour harvests 2 bushels of apples which is 252 apples and is paid 45 cents

1 hour = 2 bushels of apples

1 hour = 252 apples

1 hour = 45 cents

Hence we can say fro harvesting 252 apples, an apples picker is paid 45 cents

Mathematically,

252 apples = 45 cents

One gallon of apple juice requires 40 apples

We are to calculate the labor cost of one gallon of apple juice in dollars

If : 252 apples = 45 cents

40 apples = X cents

Cross Multiply

40 × 25 = 252 × X

X = (40× 25) ÷ 252

X = 3.984063745 cents

Hence the labor cost of 40 apples = 3.984063745 cents

Approximately = 3.98 cents

Converting 3.98 cents to dollars

100 cents = 1 dollar

3.98 cents =

= 3.98/100

= 0.0398 dollars.

Therefore, the labor cost of one gallon of apple juice in dollars is 0.0398 dollars.

8 0

3 years ago