Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)
You should already know this:
1.
2.
3.
<span>So, our question is:
</span>
Plug in the first two identities I gave you.
Apply the first identity I said you needed to know on 1/(tan θ). We should get:
Multiply the first fraction by sinθ, on both the numerator and denominator.
Multiply the second fraction by cos<span>θ, on both the numerator and denominator.
</span>
Now, use the third identity I said that you needed to know to simplify the numerator.
LHS = RHS
<span>
Therefore, identity is verified.</span>
Answer:
Step-by-step explanation: eat my butt
Answer:
Step-by-step explanation:
V =
(using differentiation product rule)
plug known values in for r, h, r', and h'
We take the value of F in the inequality by taking the inequalities in group. Let the first group be:
(1) -20 ≤ 59(F - 32)
Then, the second group would be,
(2) 59(F - 32) ≤ - 15
Calculating for the values of F,
(1) -20 ≤ 59F - 1888
1888 - 20 ≤ 59F
1868 ≤ 59F
F ≥ 31.66
(2) (59)(F - 32) ≤ - 15
59F - 1888 ≤ -15
59F ≤ 1873
F ≤ 31.75
The values of F are therefore,
31.66 ≤ F ≤ 31.75
Answer:
sure where is the attachment?
Step-by-step explanation: