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3 years ago

Please help will mark brainliest.

Mathematics

1 answer:

ra1l [238]3 years ago

4 0

Answer:

shape 1, 4, 2, and 5

Step-by-step explanation:

look for the equal sizes

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7x-y=-10 (linear combination)<br> -7x+5y=-6

andreyandreev [35.5K]

(-2,-4) is the correct answer.

Hope this helps:)

5 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Helpppppp pleaseeeeeeeeeeee

Lyrx [107]

Answer:

She bought 6 erasers.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Math.<br> How do I get 37/7 for this problem?

Bezzdna [24]

Try:

37/7 - 37/7 + 1
-----------
4

7 0

3 years ago

Pleaseee helpp meeee

Marta_Voda [28]

Answer and Step-by-step explanation:

[] means to take the absolute version of the number. That means if the number is negative or positive, the outcome is always positive.

14.

-[3] = -3

15.

[5 + 9] = 14

16.

[17 - 8] = 9

#teamtrees #WAP (Water And Plant)

6 0

3 years ago