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aleksklad [387]
3 years ago
10

Help meeee will give brainlest

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0
269 hours thats the answer
Dmitry_Shevchenko [17]3 years ago
4 0

Kelly had to work for 58 days

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How do you represent a table with linear functions
patriot [66]

A table can be represented with a linear function equation as y = mx + b, where m is the slope and b is the y-intercept.

<h3>How to Represent a Table with Linear Function?</h3>

Assuming we have a table of values as shown in the image attached below, to write an equation of linear function for the table, do the following:

Pick two pairs of values, say, (1, 5) and (2, 25) and find the slope (m):

Slope (m) = change in y / change in x = (25 - 5)/(2 - 1)

Slope (m) = 20

Find the y-intercept (b) by substituting (x, y) = (1, 5) and m = 20 into y = mx + b:

5 = 20(1) + b

5 = 20 + b

5 - 20 = b

-15 = b

b = -15

Write the equation of the linear function by substituting m = 20 and b = -15 into y = mx + b:

y = 20x - 15

Learn more about the linear function on:

brainly.com/question/15602982

#SPJ1

8 0
2 years ago
Use induction to prove: For every integer n &gt; 1, the number n5 - n is a multiple of 5.
nignag [31]

Answer:

we need to prove : for every integer n>1, the number n^{5}-n is a multiple of 5.

1) check divisibility for n=1, f(1)=(1)^{5}-1=0  (divisible)

2) Assume that f(k) is divisible by 5, f(k)=(k)^{5}-k

3) Induction,

f(k+1)=(k+1)^{5}-(k+1)

=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1

=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k

Now, f(k+1)-f(k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)

f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k

f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k

Take out the common factor,

f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)      (divisible by 5)

add both the sides by f(k)

f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)

We have proved that difference between f(k+1) and f(k) is divisible by 5.

so, our assumption in step 2 is correct.

Since f(k) is divisible by 5, then f(k+1) must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number n^{5}-n is a multiple of 5.

3 0
3 years ago
Which algebraic represent 15 less than x divided by 9
polet [3.4K]
X/9 - 15
X divided ( / ) by 9 minus ( - ) 9
6 0
3 years ago
Read 2 more answers
I only need help on number 9. Find the value of Y. ​
natima [27]
6y+40=10y-32
8=4y
Y=2
3 0
3 years ago
Please help me with this
shusha [124]
The price decreased by 40%.
6 0
3 years ago
Read 2 more answers
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