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3 years ago

Which algebraic represent 15 less than x divided by 9

Mathematics

2 answers:

polet [3.4K]3 years ago

6 0

X/9 - 15
X divided ( / ) by 9 minus ( - ) 9

svet-max [94.6K]3 years ago

4 0

$15 < x \div 9$

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Need help plz help me

IgorC [24]

Step-by-step explanation:

how could we get 30x^2?

6x × 5x

<em>so</em><em>,</em>

x^2 +6x+5x+30=0

x (x+6) +5 (x+6)=0

(x+6)(x+5)=0

(x+6)=0/(x+5)=0

x=-6 or x=-5

4 0

3 years ago

Read 2 more answers

What can you say about the y-values of the two functions <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%203%5Ex-3" id="TexForm

slavikrds [6]

Answer:

a) The minimum y-value of f(x) is -3

d) The minimum y-value of g(x) is -3

Step-by-step explanation:

Given in the question that,

f(x) = 3 $^{x}$ -3

g(x) = 7x² - 3

At large negative exponents, the value approaches to zero

y = $3^{-100}-3=-3$

y = $3^{-1000}-3=-3$

y = $3^{-10000}-3=-3$

Minimum y-value of g(x) will be when x = 0

y = 7x² - 3

y = 7(0) - 3

y = -3

4 0

2 years ago

Does 15/21 and 40/56 form a proportion

Anettt [7]

Answer:

No, 15/21 and 40/56 do not form a proportion.

Step-by-step explanation:

6 0

3 years ago

Consider F and C below. F(x, y, z) = y2 sin(z) i + 2xy sin(z) j + xy2 cos(z) k C: r(t) = t2 i + sin(t) j + t k, 0 ≤ t ≤ π (a) Fi

Liono4ka [1.6K]

Answer:

a) $f (x,y,z)= xy^2\sin(z)$

b) $\int_C F \cdot dr =0$

Step-by-step explanation:

Recall that given a function f(x,y,z) then $\nabla f = (\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})$ . To find f, we will assume it exists and then we will find its form by integration.

First assume that F = $\nabla f$ . This implies that

$\frac{\partial f}{\partial x} = y^2\sin(z)$ if we integrate with respect to x we get that

$f(x,y,z) = xy^2\sin(z) + g(y,z)$ for some function g(y,z). If we take the derivative of this equation with respect to y, we get

$\frac{\partial f}{\partial y} = 2xy\sin(z) + \frac{\partial g}{\partial y}$

This must be equal to the second component of F. Then

$2xy\sin(z) + \frac{\partial g}{\partial y}=2xy\sin(z)$

This implies that $\frac{\partial g}{\partial y}=0$ , which means that g depends on z only. So $f(x,y,z) = xy^2\sin(z) + g(z)$

Taking the derivative with respect to z and making it equal to the third component of F, we get

$xy^2\cos(z)+\frac{dg}{dz} = xy^2\cos(z)$

which implies that $\frac{dg}{dz}=0$ which means that g(z) = K, where K is a constant. So

$f (x,y,z)= xy^2\sin(z)$

b) To evaluate $\int_C F \cdot dr$ we can evaluate it by using f. We can calculate the value of f at the initial and final point of C and the subtract them as follows.