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3 years ago

Which algebraic represent 15 less than x divided by 9

Mathematics

2 answers:

polet [3.4K]3 years ago

6 0

X/9 - 15
X divided ( / ) by 9 minus ( - ) 9

svet-max [94.6K]3 years ago

4 0

$15 < x \div 9$

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Work out the area of the triangle. 13m 12m and 5m

Advocard [28]

Answer:

30m²

Step-by-step explanation:

To find the area of a triangle, you need to ensure that the triangle is a right-angled triangle. We can use the Pythagoras Theorem to help us prove that.

a² + b² = c²

5² + 12² = 169

13² = 169

By converse of Pythagoras Theorem, the triangle is a right-angled triangle.

Thus, you can directly find the area of the triangle using the formula: base × height ÷ 2.

Area = 12 × 5 ÷ 2

= 30m²

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3 years ago

Need help for this assignment

Effectus [21]

The Answer is 125 hope this helped

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3 years ago

One week, 17 employees exceeded their sales quota, 13 employees met their sales quota, and 3 employees didn't meet their sales q

Arte-miy333 [17]

Answer: Option 'B' is correct.

Step-by-step explanation:

Number of employees exceeded their sales quota = 17

Number of employees met their sales quota = 13

Number of employees didn't exceed their sales quota = 3

Now, we need to find the ratio of the number employees who exceeded their sales quota to the number of employees who didn't exceed their sales quota,

$17:13+3\\=17:16$

So, Option 'B' is correct.

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3 years ago

Alisha has a 15,000 car loan with a 6 percent interest rate that is compounded annually hiw much will she have paid at the end o

Helga [31]

A = P ( 1+r )^ t

A = the future value including interest

P = the principal = $15,000

r = the annual interest rate = 6% = 0.06

t = the number of years = 5 years

A = 15,000(1 + 0.06)^5

A = $20,073.38

Answer

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3 years ago

According to an airline, flights on a certain route are on time 8080% of the time. Suppose 1111 flights are randomly selected

Sergio [31]

Answer:

a. This experiment satisfy the conditions below.

b. 0

c. 0

d. 1

e. 0

Step-by-step explanation:

a. This experiment satisfy the following conditions:

1. The experiment consists of n = 1111 identical trials, i.e., to determine if each flight is on-time or not.

2. Each trial results in success or failure, i.e., the flight is on-time or not.

3. The probability of success in each trial is the same, p = 0.8, because a flight is on-time 80% of the time.

4. The trials are independent because the 1111 flights were selected randomly.

5. Te random variable of interest is Y, the number of on-time flights observed in the n = 1111 flights.

b. P(Y = 99) = $\frac{1111!}{99!(1111-99)!}(0.8)^99(0.2)^{1111-99}$ = 0. This is the probability that 99 flights are on time and 1012 are not.

c. P(Y < 99) = $\sum_{i=1}^{98}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y}$ = 0. This is the probability that 0 flights are on-time or 1 flight is on-time or ... or 98 flights are on-time.

d. 1 - P(Y < 99) = 1 - 0 = 1. This is the probability that 99 flights are on-time or 100 flights are on-time or ... or all 1111 flights are on-time.

e. $P(77\leq Y \leq 99) = \sum_{i=77}^{99}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y}$ = 0 This is the probability that 77 flights are on-time or 78 flights are on-time or ... or 99 flights are on-time.

8 0

3 years ago